Newtonâ€™s law of cooling states that the rate of loss of heat of a body is directly proportional to the diï¬€erence in the temperature between that body and its surroundings .

**Newtonâ€™s
law of cooling**

*Newtonâ€™s law of cooling states that
the rate of loss of heat of a body is directly proportional to the di**ï¬€**erence in the temperature between
that body and its surroundings .*

The
negative sign indicates that the quantity of heat lost by liquid goes on
decreasing with time. Where,

T
= Temperature of the object

T_{s}
= Temperature of the surrounding

From
the graph in Figure 8.12 it is clear that the rate of cooling is high initially
and decreases with falling temperature.

Let
us consider an object of mass m and specific heat capacity s at temperature *T*. Let *T*_{s}* *be the
temperature of the surroundings. If* *the
temperature falls by a small amount dT in time dt, then the amount of heat lost
is,

Where
a is some positive constant.

From
equation (8.6) and (8.7)

Where
*b*_{1} is the constant of integration.
taking exponential both sides, we get

here
*b*_{2} = *e*^{b}1 = constant

A
hot water cools from 92Â°C to 84Â°C in 3 minutes when the room temperature is
27Â°C. How long will it take for it to cool from 65Â°C to 60Â°C?

The
hot water cools 8Â°C in 3 minutes. The average temperature of 92Â°C and 84Â°C is
88Â°C. This average temperature is 61Â°C above room temperature. Using equation
(8.8)

Similarly
the average temperature of 65Â°C and 60Â°C is 62.5Â°C. The average temperature is
35.5Â°C above the room temperature. Then we can write

By
diving both the equation, we get

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11th Physics : UNIT 8 : Heat and Thermodynamics : Newtonâ€™s law of cooling |

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