Physics : Alternating Current : Power in AC Circuits

EXAMPLE 4.26

A series RLC circuit which resonates at 400 kHz has 80 Î¼H inductor, 2000 pF capacitor and 50 Î© resistor. Calculate (i) Q-factor of the circuit (ii) the new value of capacitance when the value of inductance is doubled and (iii) the new Q-factor.

Solution

L = 80 Ã— 10-6H; C = 2000 Ã— 10-12 F

R = 50 Î©; *f*r = 400 Ã— 103Hz

EXAMPLE 4.27

A capacitor of capacitance 10-4 /Ï€ F, an inductor of inductance 2/ Ï€ H and a resistor of resistance 100 Î© are connected to form a series RLC circuit. When an AC supply of 220 V, 50 Hz is applied to the circuit, determine (i) the impedance of the circuit (ii) the peak value of current flowing in the circuit (iii) the power factor of the circuit and (iv) the power factor of the circuit at resonance.

Solution

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12th Physics : Electromagnetic Induction and Alternating Current : Power in AC Circuits: Solved Example Problems |

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