Consider a circular wire loop of radius R, mass m kept at rest on a rough surface. Let I be the current flowing through the loop and be the magnetic field acting along horizontal as shown in Figure. Estimate the current I that should be applied so that one edge of the loop is lifted off the surface?
When the current is passed through the loop, the torque is produced. If the torque acting on the loop is increased then the loop will start to rotate. The loop will start to lift if and only if the magnitude of magnetic torque due to current applied equals to the gravitational torque as shown in Figure
The current estimated using this equation should be applied so that one edge of loop is lifted of the surface.
The coil of a moving coil galvanometer has 5 turns and each turn has an effective area of 2 × 10-2 m2. It is suspended in a magnetic field whose strength is 4 × 10-2 Wb m-2. If the torsional constant K of the suspension fibre is 4 × 10-9 N m deg-1.
(a) Find its current sensitivity in degree per micro - ampere.
(b) Calculate the voltage sensitivity of the galvanometer for it to have full scale deflection of 50 divisions for 25 mV.
(c) Compute the resistance of the galvanometer.
The number of turns of the coil is 5 turns
The area of each coil is 2 × 10-2 m2
Strength of the magnetic field is 4 × 10-2 Wb m-2
Torsional constant is 4 × 10-9 N m deg-1
The resistance of a moving coil galvanometer is made twice its original value in order to increase current sensitivity by 50%. Will the voltage sensitivity change? If so, by how much?.
Yes, voltage sensitivity will change.
Voltage sensitivity is Vs = Is/R
When the resistance is doubled, then new resistance is R ′ = 2R
Increase in current sensitivity is
Hence the voltage sensitivity decreases. The percentage decrease in voltage sensitivity is