Calculate the magnetic field at a point P which is perpendicular bisector to current carrying straight wire as shown in figure.
Let the length MN = y and the point P is on its perpendicular bisector. Let O be the point on the conductor as shown in figure.
The result obtained is same as we obtained in equation (3.39).
Show that for a straight conductor, the magnetic field
In a right angle triangle OPN, let the angle ∠ OPN = θ1 which implies, ϕ1 = π /2 − θ1 and also in a right angle triangle OPM, ∠OPM = θ2 which implies, ϕ2 = π/2 + θ2
What is the magnetic field at the center of the loop shown in figure?
The magnetic field due to current in the upper hemisphere and lower hemisphere of the circular coil are equal in magnitude but opposite in direction. Hence, the net magnetic field at the center of the loop (at point O) is zero .