A cube of wood floating in water supports a 300 g mass at the centre of its top face. When the mass is removed, the cube rises by 3 cm. Determine the volume of the cube.
Let each side of the cube be l. The volume occupied by 3 cm depth of cube,
V=(3cm) × l2 = 3l2cm
According to the principle of floatation, we have
Vρg = mg ⇒ Vρ = m
ρ is density of water = 1000 kg m-3
(3l2 × 10-2m) × (1000 kgm-3)=300 × 10-3 kg
l = 10 × 10-2m = 10 cm
Therefore, volume of cube V = l3 = 1000 cm3
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