Maths Book back answers and solution for Exercise questions - Find the parametric form of vector equation and Cartesian equations of a straight line

**EXERCISE 6.5**

**1. Find the parametric form of vector equation and Cartesian equations of a straight line passing through (5, 2, 8) and is perpendicular to the straight lines = (iË† + Ë†j - Ë†k ) + s(2iË† - 2 Ë†j + Ë†k ) and = (2iË† - jË† - 3kË† ) + t(Ë†i + 2 Ë†j + 2Ë†k ) .**

**2. Show that the lines = (6iË† + Ë†j + 2Ë†k ) + s(iË† + 2 Ë†j - 3Ë†k ) and = (3Ë†i + 2 Ë†j - 2Ë†k ) + t(2Ë†i + 4 Ë†j - 5Ë†k ) are skew lines and hence find the shortest distance between them.**

**3. If the two lines intersect at a point, find the value of m .**

**4. Show that the lines y-2 =0 intersect. Also find the point of intersection.**

**5. Show that the straight lines x +1 = 2 y = -12z and x = y + 2 = 6z - 6 are skew and hence find the shortest distance between them.**

**6. Find the parametric form of vector equation of the straight line passing through (-1, 2,1) and parallel to the straight line = (2 iË† + 3 Ë†j - kË†) + t(iË† - 2 Ë†j + kË†) and hence find the shortest distance between the lines.**

**7. Find the foot of the perpendicular drawn from the point (5, 4, 2) to the line Also, find the equation of the perpendicular.**

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**Answers:**

Tags : Problem Questions with Answer, Solution , 12th Mathematics : UNIT 6 : Applications of Vector Algebra

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12th Mathematics : UNIT 6 : Applications of Vector Algebra : Exercise 6.5: Point of intersection of two straight lines | Problem Questions with Answer, Solution

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