Equation of a plane passing through two given distinct points and is parallel
to a non-zero vector
The parametric form of vector equation of the plane passing through two given distinct points A and B with position vectors and , and parallel to a non-zero vector is
Equation (1) can be written equivalently in non-parametric
vector form as
Where ( - ) and are not parallel vectors.
This is the required Cartesian equation of the plane.
Example 6.43
Find the non-parametric form of vector equation, and Cartesian equation of the plane passing through the point (0,1, −5) and parallel to the straight lines
Solution
We observe that the required plane is parallel to the vectors and passing through the point (0,1, −5) with position vector .
We observe that is not parallel to . Then the vector equation of the plane in non-parametric form is given by = 0. …(1)
If = xˆi + yˆj + zˆk is the position vector of an arbitrary point on the plane, then
from the above equation, we get the Cartesian equation of the plane as -9x + 8
y - z = 13 or 9x - 8 y + z +13 = 0 .
Find the vector parametric, vector non-parametric and Cartesian
form of the equation of the plane passing through the points (−1, 2, 0), (2, 2
−1) and parallel to the straight line
The required plane is parallel to the given line and so it is parallel to the vector = iˆ + ˆj − ˆk and he plane passes through the points = −ˆi + 2ˆj, = 2ˆi + 2ˆj − ˆk .
vector equation of the plane in parametric form is , where s, t ∈ R which implies that = (-ˆi + 2ˆj ) + s (3ˆi - ˆk )+ t (ˆi + ˆj - ˆk ) , where s, t ∈ R.
vector equation of the plane in non-parametric form is
we have ( - (-iˆ + 2ˆ j)) . (ˆi + 2ˆj + 3ˆk ) = 0 ⇒ . (ˆi + 2ˆ j + 3ˆk ) = 3
If = xˆi + yˆj + zˆk is the position vector of an arbitrary point on the plane, then
from the above equation, we get the Cartesian equation of the plane as x + 2 y
+ 3z = 3 .
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