Theorem 6.11
The vector equation of a straight line passing through a fixed point with position vector and parallel to a given vector is = + t, where t∈ R.
Proof
If is the position vector of a given point A and is the position vector of an arbitrary point P on the straight line, then
= - .
This is the vector equation of the straight line in parametric form.
Remark
The position vector of any point on the line is taken as + t.
Since is parallel to , we have × =
That is, ( − ) × = 0 .
This is known as the vector equation of the straight line in non-parametric form.
Suppose P is (x, y, z) , A is (x1 , y1 , z1 ) and = b1 ˆi + b2 ˆj + b3 ˆk . Then, substituting = x ˆi + y ˆj + z ˆk , = x1ˆi + y1ˆ j + z1 ˆk in (1) and comparing the coefficients of ˆi , ˆj, ˆk , we get
x − x1 = tb1 , y − y1 = tb2 , z − z1 = tb3 ………….(4)
Conventionally (4) can be written as
which are called the Cartesian equations or symmetric equations of a straight line passing through the point (x1, y1 , z1) and parallel to a vector with direction ratios b1, b2, b3.
(i) Every point on the line (5) is of the form (x1 + tb1 , y1 + tb2 , z1 + tb3) , where t ∈ R.
(ii) Since the direction cosines of a line are proportional to direction ratios of the line, if l, m, n are the direction cosines of the line, then the Cartesian equations of the line are
(iii) In (5), if any one or two of b1, b2 , b3 are zero, it does not mean that we are dividing by zero. But it means that the corresponding numerator is zero. For instance, If b1 ≠0, b2 ≠0 and b3 = 0 , then
(iv) We know that the direction cosines of x - axis are 1, 0,0 . Therefore, the equations of x -axis are
Similarly the equations of y -axis and z -axis are given by respectively.
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