Maths Book back answers and solution for Exercise questions - Mathematics : Different forms of Equation of a plane: Questions with Answer

**EXERCISE 6.6**

**1. Find a parametric form of vector equation of a plane which is at a distance of 7 units from the origin having 3, -4, 5 as direction ratios of a normal to it.**

**2. Find the direction cosines of the normal to the plane 12 x + 3y - 4z = 65 . Also, find the non-parametric form of vector equation of a plane and the length of the perpendicular to the plane from the origin.**

**3. Find the vector and Cartesian equations of the plane passing through the point with position vector 2 iË† + 6 Ë†j + 3kË† and normal to the vector iË† + 3 Ë†j + 5kË† .**

**4. A plane passes through the point (-1,1, 2) and the normal to the plane of magnitude 3âˆš3 makes equal acute angles with the coordinate axes. Find the equation of the plane.**

**5. Find the intercepts cut off by the plane = (6Ë†i + 4 Ë†j - 3Ë†k ) = 12 on the coordinate axes.**

**6. If a plane meets the coordinate axes at A, B, C such that the centriod of the triangle ABC is the point (u, v, w) , find the equation of the plane.**

**Answers:**

Tags : Problem Questions with Answer, Solution , 12th Mathematics : UNIT 6 : Applications of Vector Algebra

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12th Mathematics : UNIT 6 : Applications of Vector Algebra : Exercise 6.6: Equation of a plane | Problem Questions with Answer, Solution

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