Equation of a plane passing through two given distinct points and is parallel
to a non-zero vector
The parametric form of vector equation of the plane passing
through two given distinct points A and B with position vectors
and
, and parallel to a non-zero vector
is

Equation (1) can be written equivalently in non-parametric
vector form as

Where (
-
) and
are not parallel vectors.

This is the required Cartesian equation of the plane.
Example 6.43
Find the non-parametric form of vector equation, and Cartesian
equation of the plane passing through the point (0,1, −5) and parallel to the
straight lines 
Solution
We observe that the required plane is parallel to the
vectors
and passing through the point (0,1, −5) with position vector
.
We observe that
is not parallel to
.
Then the vector equation of the plane in non-parametric form is given by
= 0. …(1)

If
= xˆi + yˆj + zˆk is the position vector of an arbitrary point on the plane, then
from the above equation, we get the Cartesian equation of the plane as -9x + 8
y - z = 13 or 9x - 8 y + z +13 = 0 .
Find the vector parametric, vector non-parametric and Cartesian
form of the equation of the plane passing through the points (−1, 2, 0), (2, 2
−1) and parallel to the straight line

The required plane is parallel to the given line and so it is
parallel to the vector
= iˆ + ˆj − ˆk and
he plane passes through the points
= −ˆi + 2ˆj,
= 2ˆi + 2ˆj − ˆk .
vector equation of the plane in parametric form is
, where
s, t ∈ R which implies that
= (-ˆi + 2ˆj ) + s (3ˆi - ˆk )+ t (ˆi + ˆj - ˆk ) , where s, t ∈ R.
vector equation of the plane in non-parametric form is 

we have (
- (-iˆ + 2ˆ j)) . (ˆi + 2ˆj + 3ˆk ) = 0 ⇒
. (ˆi + 2ˆ j + 3ˆk ) = 3
If
= xˆi + yˆj + zˆk is the position vector of an arbitrary point on the plane, then
from the above equation, we get the Cartesian equation of the plane as x + 2 y
+ 3z = 3 .
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