Reduce the matrix to a row-echelon form.
Note
This is also a row-echelon form of the given matrix.
So, a row-echelon form of a matrix is not necessarily unique.
Example 1.14
Reduce the matrix to a row-echelon form.
Solution
Find the rank of each of the following matrices:
Solution
(i) Let A =. Then A is a matrix of order 3× 3. So ρ(A) ≤ min {3, 3} = 3. The highest order of minors of A is 3 . There is only one third order minor of A .
It is = 3 (6− 6) − 2 (6−6) + 5 (3 − 3) = 0. So, ρ(A) < 3.
Next consider the second-order minors of A .
We find that the second order minor = 3 − 2 = 1 ≠ 0 . So ρ(A) = 2 .
(ii) Let A = . Then A is a matrix of order 3×4 . So ρ(A) ≤ min {3, 4} = 3.
The highest order of minors of A is 3 . We search for a non-zero third-order minor of A . But
we find that all of them vanish. In fact, we have
So, ρ(A) < 3. Next, we search for a non-zero second-order minor of A .
We find that = -4+9 =5 ≠ 0 . So, ρ(A) = 2 .
Finding the rank of a matrix by searching a highest order non-vanishing minor is quite tedious when the order of the matrix is quite large. There is another easy method for finding the rank of a matrix even if the order of the matrix is quite high. This method is by computing the rank of an equivalent row-echelon form of the matrix. If a matrix is in row-echelon form, then all entries below the leading diagonal (it is the line joining the positions of the diagonal elements a11 , a22 , a33 ,L. of the matrix) are zeros. So, checking whether a minor is zero or not, is quite simple.
Find the rank of the following matrices which are in row-echelon form :
Solution
(i) Let A = . Then A is a matrix of order 3 3 × and ρ(A) ≤ 3
The third order minor |A| = = (2) (3)( 1) = 6 ≠ 0 . So, ρ(A) = 3 .
Find the rank of the matrix by reducing it to a row-echelon form.
Let A = . Applying elementary row operations, we get
The last equivalent matrix is in row-echelon form. It has two non-zero rows. So, ρ (A)= 2.
Find the rank of the matrix by reducing it to a row-echelon form.
Let A be the matrix. Performing elementary row operations, we get
The last equivalent matrix is in row-echelon form. It has three non-zero rows. So, ρ(A) = 3 .
Elementary row operations on a matrix can be performed by pre-multiplying the given matrix by a special class of matrices called elementary matrices.
Show that the matrix is non-singular and reduce it to the identity matrix by elementary row transformations.
Let A = .Then, |A| = 3 (0+2 ) – 1(2+5) + 4(4-0) = 6-7+16 ≠ 0. So, A is non-singular. Keeping the identity matrix as our goal, we perform the row operations sequentially on A as follows:
Find the inverse of the non-singular matrix A = , by Gauss-Jordan method.
Applying Gauss-Jordan method, we get
Find the inverse of A = by Gauss-Jordan method.
Applying Gauss-Jordan method, we get
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