A gas contained in a cylinder fitted with a frictionless
piston expands against a constant external pressure of 1 atm from a volume of 5
litres to a volume of 10 litres. In doing so it absorbs 400 J of thermal energy
from its surroundings. Determine the change in internal energy of system.
Given data
q = 400 J
V1=5L
V2 = 10L
∆u = q-w (heat is given to the system (+q); work is done by the system(-w)
∆u q - PdV
= 400 J - 1 atm (10-5)L
=400 J - 5 atm L
[∴ 1 L atm = 101.33 J]
=400 J - 5 × 101.33 J
=400 J - 506.65 J
=- 106.65 J
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