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Chapter: 9th Maths : UNIT 3 : Algebra

Factorisation using Identity

Algebra: Factorisation using Identity

Factorisation using Identity

(i) a 2 + 2ab + b 2 ≡ (a +b)2

(ii) a 2 − 2ab +b2 ≡ (a −b)2

(iii) a2 − b2 ≡ (a + b )(a −b)

(iv) a 2 + b 2 +c 2 + 2ab + 2bc + 2ca ≡ (a + b +c)2

(v) a 3 + b 3 ≡ (a + b )(a 2 −ab +b2 )

(vi) a 3 − b 3 ≡ (a − b )(a 2 +ab +b2 )

(vii) a 3 + b 3 +c 3 − 3abc ≡ (a + b +c )(a 2 + b 2 +c2 − ab −bc −ca)

Note

 (a + b )2 +(a − b)2 = 2(a2 + b2 ); a4 −b4 = (a2 +b2 )(a + b )(a −b)

 (a + b )2 −(a −b)2 = 4ab ; a6 − b6 = (a +b)(a − b )(a2 −ab + b2 )(a2 +ab +b2 )

Progress Check


Example 3.25

Factorise the following:

(i) 9x2 + 12xy + 4y2 (ii) 25a2 − 10a +1 (iii) 36m2 − 49n2 (iv) x3 –x (v) x4 − 16 (vi) x2 + 4y2 + 9z2 − 4xy +12yz −6xz

Solution

(i) 9x2 + 12xy + 4y2 = (3x )2 + 2(3x )(2y ) +(2y)2 [ a 2 + 2ab + b2 = (a +b)2 ]

 = (3x + 2y)2

(ii) 25a2 − 10a +1 = (5a )2 −2(5a )(1) +12

= (5a −1)2    [ a 2 − 2ab + b2 = (a − b)2 ]

(iii) 36m2 − 49n2. = (6m)2 -(7n)2

= (6m + 7n)(6m −7n)               [a 2 − b2 = (a + b)(a −b)]

(iv) x3 − x = x (x2 −1)

= x(x 2 −12 )

= x (x +1)(x −1)

(v) x4 -16 = x4 -24         [a4 − b4 =(a2 + b2)(a + b)(a − b)]

 = (x 2 + 22 )(x2 −22 )

 = (x 2 + 4)(x + 2)(x −2)

(vi) x 2 + 4y 2 + 9z 2 − 4xy +12yz −6xz

 = (−x )2 + (2y )2 + (3z )2 + 2(−x )(2y ) + 2(2y)(3z ) + 2(3z)(−x)

 = (−x + 2y + 3z)2 or (x − 2y − 3z)2

Example 3.26

Factorise the following:

(i) 27x 3 +125y3

(ii) 216m 3 − 343n3

(iii) 2x4 -16xy3

(iv) 8x3 + 27y3 + 64z3 − 72xyz

Solution

(i) 27x3 +125y3

 = (3x)3 +(5y)2     [ (a3 + b3 ) = (a + b)(a2 − ab + b2 ) ]

= (3x + 5y)((3x)2 − (3x)(5y ) + (5y)2 )

= (3x + 5y)(9x2 − 15xy + 25y2 )

(ii) 216m 3 − 343n3 = (6m )3 −(7n)3         [a3− b3 ) = (a − b)(a 2+ ab + b2 )]

= (6m − 7n) ((6m )2 + (6m)(7n ) + (7n)2 )

= (6m −7n)(36m 2 + 42mn + 49n2 )

(iii) 2x4 − 16xy3 = 2x (x 3 − 8y3 )

= 2x (x3 −(2y)3 )      [(a3 − b3 ) = (a − b)(a2 + ab + b2)]

= 2x ((x − 2y )(x2 + (x)(2y) + (2y)2 ))

= 2x (x −2y )(x2 + 2xy +4y2 )

(iv) 8x3 + 27y3 + 64z3 −72xyz

= (2x)3 + (3y)3 + (4z)3 − 3(2x)(3y)(4z )

= (2x + 3y + 4z )(4x 2 + 9y 2 + 16z 2 −6xy − 12yz − 8xz)

Thinking Corner

Check 15 divides the following

(i) 20173 + 20183

(ii) 20183 – 19733

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