Maths : Algebra: Book Back, Exercise, Example Numerical Question with Answers, Solution : Exercise 3.12: Elimination Method of Solving simultaneous linear equations in Two Variables :

Exercise 3.12

1. Solve by the method of elimination

(i) 2*x*–*y* = 3; 3*x* + *y* = 7

(ii) *x*–*y* = 5; 3*x* + 2*y* = 25

(iii)* x*/10* *+* y*/5* *= 14;* x*/8* *+* y*/6* *= 15

(iv) 3(2*x* + *y*) = 7*xy*; 3(*x* + 3*y*) = 11*xy*

(v) 4/*x* + 5y = 7; 3/*x* + 4* y *= 5

(vi) 13*x* + 11*y* = 70; 11*x* + 13*y* = 74

2. The monthly income of *A* and *B* are in the ratio 3:4 and their monthly expenditures are in the ratio 5:7. If each saves ₹ 5,000 per month, find the monthly income of each.

3. Five years ago, a man was seven times as old as his son, while five year hence, the man will be four times as old as his son. Find their present age.

Tags : Solving simultaneous linear equations in Two Variables | Numerical Problems with Answers, Solution | Algebra | Maths , 9th Maths : UNIT 3 : Algebra

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9th Maths : UNIT 3 : Algebra : Exercise 3.12: Solving by Elimination Method | Solving simultaneous linear equations in Two Variables | Numerical Problems with Answers, Solution | Algebra | Maths

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