The limiting molar conductance Λ0m is the basis for kohlraush law. At infinite dilution, the limiting molar conductivity of an electrolyte is equal to the sum of the limiting molar conductivities of its constituent ions. i.e., the molar conductivity is due to the independent migration of cations in one direction and anions in the opposite direction.
For a uni – univalent electrolyte such as NaCl, the Kohlraush's law is expressed as
(Λ0m )NaCl = ( λ0m )Na+ + ( λ0m )Cl-
In general, according to Kohlraush's law, the molar conductivity at infinite dilution for a electrolyte represented by the formula Ax By , is given below.
(Λ0m)AxBy = x ( λ0m )Ay+ + y ( λ0m )Bx- .....(9.13)
Kohlraush arrived the above mentioned relationship based on the experimental observations such as the one as shown in the table. These result show that at infinite dilution each constituent ion of the electrolyte makes a definite contribution towards the molar conductance of the electrolyte irrespective of nature of other ion with which it is associated
i.e.,
(Λºm )KCl − ( Λºm)NaCl = 149.86 - 126.45
{( λºm )K+ + ( λºm )Cl- } – {( λºm )Na+ + ( λºm)Cl- } = 23.41
( λºm ) K+ - ( λºm )Na+ = 23.41
Similarly, we can conclude that ( λºm )Br- − ( λºm )Cl- = 2.06
It is impossible to determine the molar conductance at infinite dilution for weak electrolytes experimentally. However, the same can be calculated using Kohlraush’s Law.
For example, the molar conductance of CH3COOH, can be calculated using the experimentally determined molar conductivities of strong electrolytes HCl, NaCl and CH3COONa .
ΛºCH3COONa = λºNa+ + λºCHCOO- .....(1)
ΛºHCl = λºH+ + λºCl- .....(2)
ΛºNaCl = λºNa+ + λºCl- .....(3)
Equation (1) + Equation (2) – Equation (3) gives,
ΛºCH3COONa + ΛºHCl - ΛºNaCl = λoH+ + λoCH3COO-
= ΛºCH3COOH
The degree of dissociation of weak electrolyte can be calculated from the molar conductivity at a given concentration and the molar conductivity at infinite dilution using the following expression
Calculation of dissociation constant using Λm values. According to Ostwald dilution Law,
Substitute α value in the above expression ( 9.15)
Substances like AgCl, PbSO4 etc., are sparingly soluble in water. The solubility product of such substances can be determined using conductivity measurements.
Let us consider AgCl as an example
AgCl (s) ↔ Ag+ + Cl−
Ksp = [Ag+ ][Cl- ]
Let the concentration of [Ag + ] be ‘C’ molL–1.
As per the stoichiometry, if [Ag+ ] = C, then [Cl−]also equal to ‘C’ mol L−1 .
Ksp =C.C
Ksp = C2
We know that the concentration (in mol dm-3) is related to the molar and specific conductance by the following expressions
Substitute the concentration value in the relation Ksp = C2
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