Cell reactions
Na+ ions are attracted towards cathode, where they combine
with the electrons and reduced to liquid sodium.
Cathode (reduction)
Na+ (l ) + e-
→ Na (l) Eo = -2.71V
Similarly, Cl– ions are attracted towards anode where they
lose their electrons and oxidised to chlorine gas.
Anode (oxidation)
2Cl- (l) → Cl2
(g) + 2e- Eo = -1.36V
The overall reaction is,
2Na+ (l ) + 2Cl-
(l) → 2Na(l ) + Cl2
(g ) Eo
= - 4.07V
The negative Eo value shows that the above reaction is a non
spontaneous one. Hence, we have to supply a voltage greater than 4.07V to cause
the electrolysis of molten NaCl.
In electrolytic cell, oxidation occurs at the anode and reduction occur
at the cathode as in a galvanic cell, but the sign of the electrodes is the
reverse i.e., in the electrolytic cell cathode is –ve and anode is +ve.
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