Gravitational
potential energy near the surface of the Earth
It
is already discussed in chapter 4 that when an object of mass m is raised to a
height h, the potential energy stored in the object is mgh (Figure 6.14). This
can be derived using the general expression for gravitational potential energy.
Consider
the Earth and mass system, with r,
the distance between the mass m and the Earth’s centre. Then the gravitational
potential energy,
Here
r = Re+h, where Re is the radius of the Earth. h is the
height above the Earth’s surface
If
h << Re, equation (6.31) can be modified as
By
using Binomial expansion and neglecting the higher order terms, we get
We
know that, for a mass m on the Earth’s surface,
Substituting
equation (6.34) in (6.33) we get,
It
is clear that the first term in the above expression is independent of the
height h. For example, if the object is taken from height h1 to h2,then
the potential energy at h1 is
The
potential energy difference between h1 and h2 is
The
term mgRe in equations
(6.36) and (6.37) plays no role in the result. Hence in the equation (6.35) the
first term can be omitted or taken to zero. Thus it can be stated that The
gravitational potential energy stored in the particle of mass m at a height h
from the surface of the Earth is U = mgh. On the
surface of the Earth, U = 0, since h is zero.
It
is to be noted that mgh is the work done on the particle when we take the mass
m from the surface of the Earth to a height h. This work done is stored as a
gravitational potential energy in the mass m. Even though mgh is gravitational
potential energy of the system (Earth and mass m), we can take mgh as the
gravitational potential energy of the mass m since Earth is stationary when the
mass moves to height h.
Related Topics
Privacy Policy, Terms and Conditions, DMCA Policy and Compliant
Copyright © 2018-2023 BrainKart.com; All Rights Reserved. Developed by Therithal info, Chennai.