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# Book Back Numerical Problems

Physics : Kinetic Theory of Gases : Book Back Exercise, Example Numerical Question with Answers, Solution : Book Back Numerical Problems

### Numerical Problems

1. A fresh air is composed of nitrogen N2(78%) and oxygen O2(21%). Find the rms speed of N2 and O2 at 20°C.

Solution:

For Nitrogen,

Molar mass m = 0.0280 kg/mol

Temperature T = 20°C = 20 + 273 = 293K Ans: For vrms = 511 m s-1

For O2vrms = 478 m s-1

2. If the rms speed of methane gas in the Jupiter’s atmosphere is 471.8 m s-1, show that the surface temperature of Jupiter is sub-zero.

Solution:

RMS speed of methane gas = 471.8 ms-1 =Vrms

Sub-zero temperature Molar mass of methane gas

= 16.04 × 10-3 kg mol-1

Surface temperature of Jupiter T = ?

Gas constant R =8.31 Ans: -130°C

3. Calculate the temperature at which the rms velocity of a gas triples its value at S.T.P. Ans: T1 = 273 K, T2 = 2457 K

4. A gas is at temperature 80°C and pressure 5 × 10-10N m-2. What is the number of molecules per m3 if Boltzmann’s constant is 1.38 × 10-23 J K-1

Solution:

Temperature of gas T = 80°C = 80 + 273 = 353K

Pressure of gas P = 5 × 10-10 Nm-2

Boltzmann’s constant k = 1.38 × 10-23 Jk-1

Volume of gas V = 1 m3

No. of molecules n = ? Ans: 1.02 × 1011

5. From kinetic theory of gases, show that Moon cannot have an atmosphere (Assume k = 1.38 × 10-23 J K-1 Temperature T=0°C=273K).

Ans: vescape = vrms= 1.86 km s-1

6. If 1020 oxygen molecules per second strike 4 cm2 of wall at an angle of 30° with the normal when moving at a speed of 2 × 103 m s-1, find the pressure exerted on the wall. (mass of 1 atom = 1.67 × 10-27 kg)

Solution

Mass of 1 O2 atom = 2.67 × 10-26 kg

Mass of 1020 O2 atom = 2.67 × 10-26 kg

= 26.72 × 10-27 × 1020

Momentum P = mv

= 26.72 × 10-7 × 8 × 2 × 103

= 427.5 × 10-4 kgm s-1

Component of momentum normal to wall is 30°

= 427.5 ×10-4 × cos 30° . Ans: 92.4 N m-2

7. During an adiabatic process, the pressure of a mixture of monatomic and diatomic gases is found to be proportional to the cube of the temperature. Find the value of γ = (Cp/CV)

Solution Ans: 3/2

8. Calculate the mean free path of air molecules at STP. The diameter of N2 and O2 is about 3 × 10-10 m

Solution Ans: λ≈9 × 10-8 m

9. A gas made of a mixture of 2 moles of oxygen and 4 moles of argon at temperature T. Calculate the energy of the gas in terms of RT. Neglect the vibrational modes. Ans: 11RT

10. Estimate the total number of air molecules in a room of capacity 25 m3 at a temperature of 27°C.

Solution:

Volume of the room V = 25.0m3

Temperature of the room T = 27°C = 300K

Pressure in the room P = estimate

= 1 × 1.013 × 105 Pa

The ideal gas equation relating pressure (P), volume (v) absolute temperature (T) can be written is

PV = KB NT Ans: 6.1 × 1026 molecules

Tags : Kinetic Theory of Gases | Physics , 11th Physics : UNIT 9 : Kinetic Theory of Gases
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