A prism is a transparent medium bounded by the three plane faces. Out of the three faces, one is grounded and the other two are polished. The polished faces are called refracting faces.

**Prism**

A prism is a
transparent medium bounded by the three plane faces. Out of the three faces,
one is grounded and the other two are polished. The polished faces are called
refracting faces. The angle between the refracting faces is called angle of
prism, or the refracting angle. The third face is called base of the prism.

*Refraction of light
through a prism*

Fig. shows the cross
section of a triangular prism ABC, placed in air. Let ?A? be the refracting
angle of the prism. A ray of light PQ incident on the
refracting face AB, gets refracted along QR and emerges along RS. The angle of
incidence and refraction at the two faces are i_{1}, r_{1} , r_{2} and i_{2 } respectively. The angle between the incident
ray PQ and the emergent ray RS is called angle of deviation, d. In the ∆QER,
the exterior angle FER = angle EQR +
angle ERQ

*d = (i _{1} - r_{1}) + (i_{2} - r_{2})*

*d = (i _{1} + i_{2})
- (r_{1} + r_{2})
????.(1)*

In the quadrilateral *AQOR*, the angles at *Q* and *R* are right angles

Angle Q + Angle R =
180^{0}

A + Angle R = 180^{0} ????.(2)

Also, from the ∆*QOR*

*r _{1}+ r_{2} = A ??????..(4)*

*Substituting in (1),*

*d = i _{1} + i_{2} - A*

*or A + d = i _{1} + i_{2} ...(5)*

*For a given prism and for a light of given wavelength, the angle
of deviation depends upon the angle of incidence.*

*As the angle of incidence i gradually increases, the angle of
deviation d decreases, reaches a minimum value D and then*

*increases. D is called the angle of minimum deviation. It will
be seen from the graph (Fig. ) that there is only one angle of*

*incidence for which the deviation is a minimum. *

*At minimum deviation position the incident ray and emergent ray
are symmetric with respect to the base of the prism. (i.e)the refracted ray QR
is parallel to the base of the prism.*

*At the minimum deviation *

*i _{1} = i_{2}
= i and r_{1} = r_{2}
= r*

*from equation (4) 2r = A or r = A/2*

*and from equation (5) 2i = A + D or i = ( A+D )/2*

*The refractive index is ? = sin i/sin r*

*? = [sin((A+D) / 2)] / sin(A/2)*

Study Material, Lecturing Notes, Assignment, Reference, Wiki description explanation, brief detail

**Related Topics **

Copyright © 2018-2020 BrainKart.com; All Rights Reserved. Developed by Therithal info, Chennai.