Spring constant or force constant, also called as stiffness constant, is a measure of the stiffness of the spring.

Combinations of springs

Spring constant or force constant, also called as stiffness constant, is a measure of the stiffness of the spring. Larger the value of the spring constant, stiffer is the spring. This implies that we need to apply more force to compress or elongate the spring. Similarly, smaller the value of spring constant, the spring can be stretched (elongated) or compressed with lesser force. Springs can be connected in two ways. Either the springs can be connected end to end, also known as series connection, or alternatively, connected in parallel. In the following subsection, we compute the effective spring constant when

a. Springs are connected in series

b. Springs are connected in parallel

When two or more springs are connected in series, we can replace (by removing) all the springs in series with an equivalent spring (effective spring) whose net effect is the same as if all the springs are in series connection. Given the value of individual spring constants *k*1,* k*2,* k*3,... (known quantity), we can* *establish a mathematical relationship to find out an effective (or equivalent) spring constant *ks* (unknown quantity). For simplicity, let us consider only two springs whose spring constant are *k*1* *and* k*2* *and which can be attached to* *a mass *m* as shown in Figure 10.17. The results thus obtained can be generalized for any number of springs in series.

Let *F* be the applied force towards right as shown in Figure 10.18. Since the spring constants for different spring are different and the connection points between them is not rigidly fixed, the strings can stretch in different lengths. Let *x*1 and *x*2 be the elongation of springs from their equilibrium position (un-stretched position) due to the applied force *F*. Then, the net displacement of the mass point is

From Hooke’s law, the net force

For springs in series connection

−*k*1*x*1 = −*k*2*x*2 = *F*

Therefore, substituting equation (10.39) in equation (10.38), the *effective spring constant* can be calculated as

Suppose we have *n* springs connected in series, the effective spring constant in series is

If all spring constants are identical i.e., *k*1 = *k*2* *=... =* k*n* *=* k *then

This means that the effective spring constant reduces by the factor *n*. Hence, for springs in series connection, the effective spring constant is lesser than the individual spring constants.

From equation (10.39), we have,

*k*1*x*1* *=* k*2*x*2

Then the ratio of compressed distance or elongated distance *x*1 and *x*2 is

The elastic potential energy stored in first and second springs are V1=1/2 k1x12 and V2=1/2 k2x22 respectively. Then, their ratio is

Consider two springs whose force constants are 1 N m−1 and 2 N m−1 which are connected in series. Calculate the effective spring constant (*ks* ) and comment on *ks* .

*ks *<* k*1* *and* ks *<* k*

Therefore, the effective spring constant is lesser than both *k*1 and *k*2.

When two or more springs are connected in parallel, we can replace (by removing) all these springs with an equivalent spring (effective spring) whose net effect is same as if all the springs are in parallel connection. Given the values of individual spring constants to be *k*1,*k*2,*k*3, ... (known quantities), we can establish a mathematical relationship to find out an effective (or equivalent) spring constant *k*p* *(unknown quantity). For simplicity, let us* *consider only two springs of spring constants *k*1and* k*2* *attached to a mass* m *as shown in* *Figure 10.19. The results can be generalized to any number of springs in parallel.

Let the force *F* be applied towards right as shown in Figure 10.20. In this case, both the springs elongate or compress by the same amount of displacement. Therefore, net force for the displacement of mass *m* is

where *k*p is called *effective spring constant*. Let the first spring be elongated by a displacement *x* due to force *F*1 and second spring be elongated by the same displacement *x *due to force* F*2, then the net force

Equating equations (10.46) and (10.45), we get

Generalizing, for n springs connected in parallel,

If all spring constants are identical i.e., *k*1* *=* k*2= ... =* kn *=* k *then

This implies that the effective spring constant increases by a factor *n*. Hence, for the springs in parallel connection, the effective spring constant is greater than individual spring constant.

Consider two springs with force constants 1 N m−1 and 2 N m−1 connected in parallel. Calculate the effective spring constant (*kp* ) and comment on *kp*.

*k1 *= 1 N m−1,* k2 *= 2 N m−1

*kp *=* k*1* *+* k*2* *N m−1

*kp *= 1 + 2 = 3 N m−1

*kp *>* k*1* *and* kp *>* k*2

Therefore, the effective spring constant is greater than both *k*1 and *k*2.

Calculate the equivalent spring constant for the following systems and also compute if all the spring constants are equal:

*Solution*

a. Since *k*1 and *k*2 are parallel, *k*u = *k*1 + *k*2 Similarly, *k*3 and *k*4 are parallel, therefore, *k*d = *k*3 + *k*4

But *k*u and *k*d are in series,

If all the spring constants are equal then, *k*1 = *k*2 = *k*3 = *k*4 = *k*

Which means, *k*u = 2*k* and *k*d = 2*k*

b. Since *k*1 and *k*2 are parallel, *k*A = *k*1 + *k*2 Similarly, *k*4 and *k*5 are parallel, therefore, *k*B = *k*4 + *k*5

But *k*A, *k*3, *k*B, and *k*6 are in series,

If all the spring constants are equal then, *k*1 = *k*2 = *k*3 = *k*4 = *k*5 = *k*6 = *k* which means, *k*A = 2*k* and *k*B = 2*k*

*keq *= k/3

A mass *m* moves with a speed *v* on a horizontal smooth surface and collides with a nearly massless spring whose spring constant is *k*. If the mass stops after collision, compute the maximum compression of the spring.

When the mass collides with the spring, from the law of conservation of energy “the loss in kinetic energy of mass is gain in elastic potential energy by spring”.

Let *x* be the distance of compression of spring, then the law of conservation of energy

Study Material, Lecturing Notes, Assignment, Reference, Wiki description explanation, brief detail

11th Physics : UNIT 10 : Oscillations : Combinations of springs - Linear Simple Harmonic Oscillator (LHO) |

**Related Topics **

Privacy Policy, Terms and Conditions, DMCA Policy and Compliant

Copyright © 2018-2023 BrainKart.com; All Rights Reserved. Developed by Therithal info, Chennai.