Tangent to a plane curve is a straight line touching the curve at exactly one point and a straight line perpendicular to the tangent and passing through the point of contact is called the normal at that point.

**Tangents and Normals to Conics**

Tangent to a plane curve is a straight line touching the curve at
exactly one point and a straight line perpendicular to the tangent and passing
through the point of contact is called the normal at that point.

Let *P *( *x*_{1} , *y*_{1} ) and
*Q *( *x*_{2} , *y*_{2} ) be two points on a
parabola *y*^{2} = 4*ax *.

Then, *y*_{1}^{2}
= 4*ax*_{1}* *and
*y*_{2}^{2}
= 4*ax _{2}*,

and *y _{1}*

Simplifying, , the slope of the chord PQ.

Thus , represents the equation of the chord PQ.

When *Q *→ *P *, or *y*_{2} → *y*_{1}
the chord becomes tangent at *P*.

Thus the equation of tangent at (*x*_{1} , *y*_{1})
is

*y* – *y*_{1} = 4*a*/2*y*_{1} (*x* - *x*_{1})
where 2*a/y _{1}* is the slope
of the tangent ... (1)

*yy*_{1} – *y _{1}*

*yy*_{1} - 4*ax*_{1} = 2*ax *- 2*ax*_{1}

** yy_{1} **=

Equation of tangent at (*at*^{2} , 2*at*) on
the parabola is

*y*(2*at*) = 2*a*(*x *+ *at*^{2})

** yt **=

From (1) the slope of normal is* − *y_{1}_{1}*/2a*

Therefore **equation of the normal **is

2*ay *− 2*ay*_{1} = − *y*_{1}*x
*+ *y*_{1}*x*_{1}

*xy*_{1} + 2*ay* = *y*_{1}( *x*_{1} + 2*a*)

** xy_{1} **+

Equation of the normal at (*at*^{2} , 2*at*)
on the parabola is

*x*2*at *+ 2*ay *= *at*^{2} (2*at*) + 2*a*(2*at*)

2*a*(*xt *+ *y*) = 2*a*(*at*^{3}
+ 2*at*)

** y **+

Three normals can be drawn to a parabola *y*^{2} =
4*ax *from a given point, one of which is always real.

*y*^{2} = 4*ax *is the given parabola. Let (*α*, *β*) be
the given point.

Equation of the normal in parametric form is

*y *= – *tx *+ 2*at *+ *at*^{3} ... (1)

If *m *is the slope of the normal then *m *= −*t *.

Therefore the equation (1) becomes *y *= *mx *− 2*am
*− *am*^{3}.

Let it passes through (*α*, *β*) , then

*β *= *ma *− 2*am *− *am*^{3}

*am*^{3} + (2*a *− *α*)*m *+ *β *= 0

which being a cubic equation in *m *, has three values of *m
*. Consequently three normals, in general, can be drawn from a point to the
parabola, since complex roots of real equation, always occur in conjugate pairs
and (1) being an odd degree equation, it has atleast one real root. Hence
atleast one normal to the parabola is real.

(1) Equation of the tangent to the ellipse

(2) Equation of the normal to the ellipse

(3) Equation of the tangent to the hyperbola

(4) Equation of the normal to the hyperbola

Let (*x*_{1} , *y*_{1} ) be the point
on the parabola *y*^{2} = 4*ax *. Then *y _{1}*

Let *y *= *mx *+ *c *be the tangent to the
parabola ..
(2)

Equation of tangent at ( *x*_{1} , *y*_{1}
) to the parabola from 5.6.1 is *yy*_{1} = 2*a *( *x *+
*x*_{1} ) …. (3)

Since (2) and (3) represent the same line, coefficients are
proportional.

So the point of contact is ( *a/m _{2} *, 2

The condition for the line *y *= *mx *+ *c *to be
tangent to the ellipse or hyperbola can be derived as follows in the same way
as in the case of parabola.

Condition for line *y = mx +
c* to be the tangent to the ellipse is *c*^{2} = *a*^{2}*m*^{2}
+ *b*, with the point of contact is and the equation of
tangent is *y* = *mx* ± √[*a ^{2}m^{2}+b^{2}*] = .

**(iii) Hyperbola **

Condition for line *y = mx +
c *to be the tangent to the hyperbola is c^{2} = a^{2}m^{2} – b^{2}, with the point of contact is and the equation of tangent is *y* = *mx* ± √[*a ^{2}m^{2
}*-

(1) In *y = mx ± *, either *y = mx + * or *y =
mx – ** *is the equation to the tangent of ellipse but not both.

(2) In *y = mx ± *, either *y = mx + ** *or *y = mx – ** *is the
equation to the tangent of hyperbola but not both.

(1) Two tangents can be drawn to (i) a parabola (ii) an ellipse
and (iii) a hyperbola, from any external point on the plane.

(2) Four normals can be drawn to (i) an ellipse and (ii) a
hyperbola from any external point on the plane.

(3) The locus of the point of intersection of perpendicular
tangents to

(i) the parabola *y*^{2} = 4*ax *is *x *=
−*a**
*(the directrix).

(ii) the ellipse ( called the director circle
of ellipse).

(iii) the hyperbola (called director circle of hyperbola).

Find the equations of tangent and normal to the parabola *x*^{2}
+ 6*x *+ 4 *y *+ 5 = 0 at (1, −3).

Equation of parabola is *x*^{2} + 6*x *+ 4 *y *+
5 = 0 .

*x*^{2} + 6*x *+ 9 − 9 + 4 *y *+ 5 = 0

(*x *+ 3)^{2} = −4( *y *−1)

Let *X *= *x *+ 3,*Y *= *y *−1

Equation (1) takes the standard form

*X*^{2} = −4*Y*

Equation of tangent is *XX*_{1} = −2(*Y *+ *Y*_{1}
)

At (1, −3) *X*_{1} = 1+ 3 = 4; *Y*_{1}
= −3 −1 = −4

Therefore, the equation of tangent at (1, −3) is

(*x *+ 3)4 = −2( *y *−1− 4)

2*x *+ 6 = − *y *+ 5 .

2*x *+ *y *+1 = 0 .

Slope of tangent at (1, −3) is −2 , so slope of normal at (1,
−3) is ½

Therefore, the equation of normal at (1, −3) is given by

*y *+ 3 = 1/2 (*x*−1)

2 *y *+ 6 = *x *−1

*x *− 2 *y *− 7 = 0 .

Find the equations of tangent and normal to the ellipse *x*^{2}
+ 4 *y*^{2} = 32 when *θ *= *π/*4.

Equation of ellipse is *x*^{2} + 4*y*^{2}=
32

**Aliter**

= (4, 2)

Equation of tangent at θ = π/4 is same at ( 4, 2).

Equation of tangent in cartesian form is

* x* + 2 *y*
- 8 = 0

Slope of tangent is – 1/2

Slope of normal is 2

Equation of normal is *y - 2
= 2(x - 4)*

*y - 2x + 6 = 0.*

Tags : Equation, Definition, Theorem, Proof, Solved Example Problems , 12th Mathematics : UNIT 5 : Two Dimensional Analytical Geometry II

Study Material, Lecturing Notes, Assignment, Reference, Wiki description explanation, brief detail

12th Mathematics : UNIT 5 : Two Dimensional Analytical Geometry II : Tangents and Normals to Conics | Equation, Definition, Theorem, Proof, Solved Example Problems

**Related Topics **

Privacy Policy, Terms and Conditions, DMCA Policy and Compliant

Copyright © 2018-2023 BrainKart.com; All Rights Reserved. Developed by Therithal info, Chennai.