Limit and
Continuity of Functions of Two Variables
Suppose that A {( x ,
y) | a < x < b , c < y < d
} ⊂ ℝ2 , F : A → R. We say
that F has a limit L at (u,v) if the
following hold :
For every neighboourhood ( L − ε , L + ε ), ε > 0 , of L , there
exists a δ –neighbourhood Bδ ((u,
v )) ⊂ A of (u,v) such that
( x , y) ∈ Bδ ((u, v ))
\ {(u, v )}, δ > 0 ⇒ f (x) ∈(L − ε , L + ε ) .
We denote this by lim (
x , y ) →(u,v) F ( x, y ) = L
if such a limit exists.
When
compared to the case of a function of single variable, for a function of two
variables, there is a subtle depth in the limiting process. Here the values of F ( x,
y) should approach the same value L , as ( x , y) approaches (u , v)
along every
possible path to (u , v) (including paths that are not
straight lines). Fig.8.9 explains the limiting process.
All the rules for
limits (limit theorems) for functions of one variable also hold true for
functions of several variables.
Now,
following the idea of continuity for functions of one variable, we define
continuity of a function of two variables.
Suppose that A = {( x, y ) | a < x < b, c < y < d } ⊂ ℝ2 , F : A → ℝ. We say that F is
continuous at at (u , v) if the following hold :
(1) F is defined at (u , v)
(2) lim( x , y ) →(u,v) F ( x, y ) = L
exists
(3) L = F (u,v).
Remark
(1) In
Fig. 8.10 taking L =
F ( x0 , y0
) will illustrate continuity at ( x0
, y0 ) .
(2) Continuity
for f (x1 , x2
, , xn ) is also defined
similarly as defined above.
Let us
consider few examples as illustrations to understand continuity of functions of
two variables.
Example 8.8
Let f (x
, y) = (or) 3x−5y+8 / x2+y2+1
for all ( x , y) ∈ ℝ2. Show that f is continuous on ℝ2.
Solution
Let (a ,
b) ∈ ℝ2 be an arbitrary point. We shall
investigate continuity of f at (a ,
b).
That is,
we shall check if all the three conditions for continuity hold for f at (a , b) .
To check
first condition, note that f (a, b) = is defined.
Now we
note that limx,y→( a , b) f (x, y ) = L = f (a, b) . Hence f satisfies all the three conditions for continuity of f at (a , b) . Since (a , b) is an
arbitrary point in ℝ2 , we conclude that f is continuous at every point of ℝ2.
Example 8.9
Consider
f ( x, y) = if (
x , y) ≠ (0, 0) and f (0, 0) = 0
. Show that f is not continuous
at (0, 0) and continuous at all other points of ℝ2 .
Solution
Note
that f is defined for every ( x , y)
∈ R2 . First let us check the continuity at ( a , b)
≠
(0, 0) .
Let us
say, just for instance, (a , b) = (2, 5) . Then f (2, 5) = 10/29 . Then, as in the above
example, we calculate
it follows that f is continuous at (2, 5) .
Exactly by
similar arguments we can show that f is
continuous at every point ( a , b) ≠
(0, 0) . Now let us check the continuity at (0, 0) . Note that f (0, 0) = 0 by definition. Next we want
to find if
exists
or not.
First
let us check the limit along the straight lines y = mx , passing through
(0, 0).
So for different values of m , we get different values m / 1+ m2 and hence we conclude that does not exist. Hence f cannot be continuous at (0, 0) .
Example 8.10
Consider g ( x
, y) = if ( x , y) ≠
(0, 0) and g(0, 0) = 0. Show that g is
continuous on ℝ2.
Solution
Observe
that the function g is defined for
all ( x , y) ∈
ℝ2 . It is easy to check, as in the
above examples, that g is continuous
at all point ( x , y) ≠ (0, 0) . Next we shall check the
continuity of g at (0, 0) . For that
we see if g has a limit L at (0, 0) and if L = g(0, 0) =
0 . So we consider
Note that in the final step above we have used 2|xy| ≤ x2 + y2 (which follows by considering 0 ≤ (x − y)2 ) for all x , y ∈ ℝ. Note that ( x , y) → (0, 0) implies |x| → 0 . Then from (9) it follows that = 0 = g(0, 0) ; which proves that g is continuous at (0, 0) . So g is continuous at every point of ℝ2.
Related Topics
Privacy Policy, Terms and Conditions, DMCA Policy and Compliant
Copyright © 2018-2023 BrainKart.com; All Rights Reserved. Developed by Therithal info, Chennai.