Homogeneous
Functions and Euler’s Theorem
Definition 8.12
(a) Let A = {( x,
y ) | a < x < b, c < y < d }
⊂ ℝ2 , F : A → ℝ, we say that F is a
homogeneous function on A , if there
exists a constant p such that F ( λ x, λ y ) = λ p F ( x , y)
for all λ ∈ ℝ and sutitably
restricted λ, x, y, such that (λ x , λ y) ∈ A . This constant p is
called degree of F .
(b) Let B = {( x, y , z) | a < x < b , c < y < d, u < z < v} ⊂ ℝ3 , G : B → ℝ, we say that G is a homogeneous function on B , if there exists a constant p such that G ( λ x, λ y , λ z ) = λ pG ( x, y , z) for all λ ∈ ℝ and sutitably restricted λ, x, y, z, such that (λ x , λ y, λz ) ∈ B . This constant p is called degree of G .
Note: Division by any variable may occur, to avoid division by zero, we
say that λ, x, y, z are sutitably restricted real numbers.
These
types of functions are important in Ordinary differential equations (Chapter
10). Let us consider some examples.
Consider
F ( x, y) = x3 − 2 y3 + 5xy2 , (x
, y) ∈ ℝ2 . Then
F ( λ x ,
λ y)
= (λ x )
3 − 2(λ y)3 + 5(λ x )(λ y)2 = λ3 (x
3 − 2 y3 + 5xy2 )
and
hence F is a homogeneous function of
degree 3.
On the other
hand,
G ( x, y)
= ex2 + 3y2 is not a homogeneous function
because, G (
λ x ,
λ y)
= e (λx)2 + 3(λ y)2 ≠ λpG (
x, y)
for any λ ≠ 1 and any p.
Example 8.21
Show
that is a homogeneous function of degree 1.
Solution
We
compute
for all λ ∈ ℝ. So F is a
homogeneous function of degree 1.
We state
the following theorem of Leonard Euler on homogeneous functions.
Definition 8.13
(Euler)
Suppose that A = {( x, y ) | a < b, c < y < d }⊂ ℝ2, F : A → ℝ2 . If F is having
continuous partial derivatives and homogeneous on A , with degree p , then
Suppose that B = {( x, y , z)
| a < x < b, c < y < d, u < z < v} ⊂ ℝ3 , F : B → ℝ3. If F is having continuous
partial derivatives and homogeneous on B
, with degree p , then
We omit the proof. The above theorem is also true for any homogeneous function of n variables; and is useful in certain calculations involving first order partial derivatives.
Example 8.22
Solution
Note
that the function u is not
homogeneous. So we cannot apply Euler’s Theorem for u.
However,
note that is homogeneous;
because
Note:
Solving
this problem by direct calculation will be possible; but will involve lengthy
calculations.
Related Topics
Privacy Policy, Terms and Conditions, DMCA Policy and Compliant
Copyright © 2018-2023 BrainKart.com; All Rights Reserved. Developed by Therithal info, Chennai.