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Chapter: 11th Chemistry : UNIT 14 : Haloalkanes and Haloarenes

Brief questions and answers: Chemistry: Haloalkanes and Haloarenes

Brief questions and answers: Chemistry: Haloalkanes and Haloarenes

Haloalkanes and Haloarenes | Chemistry

Answer the following questions

26. Classify the following compounds in the form of alkyl, allylic, vinyl, benzylic halides

i. CH3 – CH = CH – Cl

ii. C6H5CH2I


iv. CH2 = CH – Cl


a) CH3-CH = CH-Cl - Vinylic halide

b) C6H5CH2I - Benzylic halide

c)  - Alkyl halide

d) CH2 = CH-Cl - Vinylic halide


27. Why chlorination of methane is not possible in dark?

Chlorination of methane is a free radical substitution reaction. If chlorination of methane is carriedout in dark, the energy will not be sufficient to undergo homolytic fission of chlorine to produce chlorine free radical.


28. How will you prepare n propyl iodide from n-propyl bromide?

When n-propyl bromide on heating with concentrate solution of sodium iodide in dry acetone forms n-propyl iodide. This reaction is called Finkelstein reaction.

CH3CH2CH2Br + NaI __acetone_Δ_→ CH3CH2CH2I + NaBr


29. Which alkyl halide from the following pair is i) chiral ii) undergoes faster SN2 reaction?


30. How does chlorobenzene react with sodium in the presence of ether? What is the name of the reaction?

Chlorobenzene react with sodium in the presence of dry ether gives biphenyl. This reaction is called fittig reaction.

C6H5Cl + 2Na + Cl - C6H5 EtherΔ__→ C6H5 - C6H5 +2NaCl


31. Give reasons for polarity of C-X bond in halo alkane.

In haloalkane, halogen atom is more electronegative than carbon. So, the shared pair of electron lies closer to the halogen atom. As a result, the halogen carries a small negatives charge δ while the carbon carries a small positive charge (δ+). Thus, C - X bond is a polar bond.


32. Why is it necessary to avoid even traces of moisture during the use of Grignard reagent?

Grignard reagent is highly reactive towards moisture to give alkane


33. What happens when acetyl chloride is treated with excess of CH3MgI?

Acetyl Chloride reacts with excess methyl magnesium iodide to give tert - butyl alcohol.

34. Arrange the following alkyl halide in increasing order of bond enthalpy of RX

CH3Br, CH3F, CH3Cl, CH3I

The increasing order of bond enthalpy of alkyl halides are. CH3I < CH3Br < CH3Cl < CH3F


35. What happens when chloroform reacts with oxygen in the presence of sunlight?

Chloroform undergoes oxidation in the presence of light and air to form a poisonous gas, carbonyl chloride also known as phosgene.


36. Write down the possible isomers of C5H11Br and give their IUPAC and common names.

The possible isomers of C5H11Br are


37. Mention any three methods of preparation of haloalkanes from alcohols.

From alcohols:

a) Reaction with hydrogen halide: Alcohols react with hydrogen halide to yield haloalkanes.

R - OH + HX → R-X + H2O

Example : CH3CH2OH + HCl ___anhy ZnCl2→ CH3CH2C1 + H2O

b) Reaction with Phosphurous halides :

Alcohol react with PX5 or PX3 to form haloalkanes.

R - OH + PX5 → R - X + POX3+ HX

Example : CH3CH2OH + PCl5 → CH3CH2Cl+ POCl3 + HCl

c) Reaction with thionyl chloride :

Alcohols are refuxed with SOCl2 in the presence of small amount of pyridine to give chloroalkane. (Darzen's Reaction)

R - OH + SOCl2 __pyridine__→ R - Cl + SO2 + HCl

Example : CH3CH2OH + SOCl2 __pyridine__→ CH3CH3Cl + SO2 + HCl


38. Compare SN1 and SN2 reaction mechanisms.


39. Reagents and the conditions used in the reactions are given below. Complete the table by writing down the product and the name of the reaction.



40. Discuss  the  aromatic  nucleophilic substitutions reaction of chlorobenzene.

Aromatic nucleophilic substitution reaction :

Halo arenes do not undergo nucleophilic substitution reaction readily. This is due to C-X bond in aryl halide is short and strong and also the aromatic ring is a centre of high electron density.

The halogen of haloarenes can be substituted by OH, NH3, or CN with appropriate nucleophilic reagents at high temperature and pressure.

Examples :


41. Account for the following

i. t-butyl chloride reacts with aqueous KOH by SN1 mechanism while n-butyl chloride reacts with SN2 mechanism.

ii. p-dichloro benzene has higher melting point than those of o-and m-dichloro benzene.

i) In general, SN1 reaction proceeds through the formation of carbo cation, t-butyl chloride reacts with aqueous KOH, it form tert - butyl chloride reacts with aqueous KOH, it form tert -butyl carbo cation which is more stable. Hence, it follow SN1 mechanism.

In the case of n-butylbromide, primary n-butyl carbo cation is formed which is least stable so, it does not follow SN1 mechanism. Hence, it follow SN2 mechanism.

ii) P - dichloro benzene has high melting point than the other two isomers due its symmetry which leads to more close packing of its molecules in the crystal lattice. Hence, it has greater intermolecular force of attraction. Therefore, it requires more energy for melting.


42. In an experiment ethyliodide in ether is allowed to stand over magnesium pieces. Magnesium dissolves and product is formed

a) Name the product and write the equation for the reaction.

b) Why all the reagents used in the reaction should be dry? Explain

c) How is acetone prepared from the product obtained in the experiment.

a) Methyl magnesium is formed as product.

CH3I + Mg _ether_→ CH3 MgI

b) Generally, Grignard reagent are highly reactive towards moisture to form alkane.


43. Write a chemical reaction useful to prepare the following:

i) Freon-12 from Carbon tetrachloride

ii) Carbon tetrachloride from carbon disulphide


44. What are Freons? Discuss their uses and environmental effects

The Chlorofluoro derivatives of methane and thane are called freons.

Uses : Freons are used as

i) refrigerants in refrigerators and air conditioners.

ii) Propellant for aerosols and foams.

iii) Propellant for foams to spray out deodorants, shaving creams and insecticides.


45. Predictthe products when bromoethane is treated with the following

i. KNO2

ii. AgNO2

i) Bromoethane reacts with alcoholic KNO2 to form ethyl nitrite.

C2H5Br + KNO2 → C2H5 - O -N = O + KBr

ii) Bromoethane react with alcoholic silver nitrite to form nitro ethane.

C2H5Br +AgNO2 → C2H5 NO2+AgBr


46. Explain the mechanism of SN1 reaction by highlighting the stereochemistry behind it

SN1 Mechanism:

SN1 stands for unimolecular nucleophilic substitution

'S' stands for substitution

‘N’ stands for nucleophilic

‘1’ stands for unimolecular (one molecule is involved in the rate determining step) The rate of the following SN1 reaction depends upon the concentration of alkyl halide (RX) and is independent of the concentration of the nucleophile (OH).

Rate of the reaciton = k [alkyl halide].

R - Cl + OH → R - OH + Cl

This SN1 reaction follows first order kinetics ans occurs in two steps.

Let us consider SN1 reaction mechanism by taking a reaction between tertiary butyl bromide with aqueous KOH.

This reaction takes place in two steps as shown below

Step −1 Formation of carbocation

The polar C - Br bond breaks forming a carboncation and bromide ion. This step is slow and hence it is the rate determining step.

The carbocation has 2 equivalent lobes of the vacant 2p orbital, so it can react equally rapidly from either face.

Step - 2 Nucleophilic attack on carbocation

As nucleophilic reagent OH can attack carbocation from both the sides, to form equal proportion of dextro and levorotatory optically active isomers which from optically inactive racemic mixture.


47. Write short notes on the the following

i. Raschig process

ii. Dows Process

iii. Darzens process

i) Raschig process

Chloro benzene is commercially prepared by passing a mixture of benzene vapour, air and HCl over heated cupric chloride. This reaction is called Raschig process.

(ii) Dows process

Reaction of Chlorobenzene with caustic soda at 350°C and 300 atm gives phenol. This reaction is used for large scale preparation as it known as Dows process.

(iii) Darzens Process

Alcohols are refluxed with SOCl2 in the presence of small amount of pyridine to give chloro alkanes.

R - OH + SOCl2  __Pyridine_→ R - Cl + SO2 + HCl


CH3CH2OH Ethanol + SOCl2 __Pyridine_→ CH3CH2Cl Chloroethane + SO2 + HCl

This reaction is known as Darzen’s reaction.


48. Starting from CH3MgI, How will you prepare the following?

i. Acetic acid

ii. Acetone

iii. Ethyl acetate

iv. Iso propyl alcohol

v. Methyl cyanide


49. Complete the following reactions



50. Explain the preparation of the following compounds

i) DDT

ii) Chloroform

iii) Biphenyl

iv) Chloropicrin

v) Freon-12

i) DDT

DDT can be prepared by heating a mixture of chlorobenzene with chloral (Trichlor) acetaldehyde) in the presence of con.H2SO4. 

ii) Chloroform

Chloroform is prepared by distilling the mixture of ethyl alcohol with a suspension of bleaching powder - The reaction proceeds in the following steps.

CaOCl2 + H2O → Ca(OH)2 + Cl2

CH3CH2OH + Cl2 → CH3CHO + 2HCl (Oxidation)

CH3CHO + 3Cl2 → CCl3CHO + 3HCI (Chlorinaiton)

2CC13CHO + Ca(OH)2 → 2CHCl3 Chloroform + (H COO)2Ca Calcium formate

iii) Biphenyl:

Chloroform react with sodium metal in dry ether gives biphenyl.

iv) Chloropicrin:

Chloroform reacts with nitric acid to from chloropicrin.

v) Freon−12

Freon−12 is prepared by the action of hydrogen fluoride on carbon tetrachloride in the presence of antimony penta chloride (SbCl3)

This reaction is called SWARTZ REACTION

CCl4 + 2HF __SbCl3→ CCl2F2 + 2HCl


51. An organic compound (A) with molecular formula C2H5Cl reacts with KOH gives compounds (B) and with alcoholic KOH gives compound (C). Identify (A),(B), and (C)



As per molecular formula, compound (A) is ethyl chloride. Ethyl chloride (A) reacts with aqueous KOH gives ethyl alcohol (B).

CH3CH2C1 (A) + aq. KOH → CH3CH2OH  (B) + KCl

 Ethyl chloride (A) with alcoholic KOH undergoes dehydrohalogenation to give ethylene (C).

CH3CH2Cl (A) + Alc. KOH → CH2 = CH2 (C) + KCl + H2O


Compound : Formula, Name

A : CH3CH2Cl Ethyl chloride

B : CH3CH2OH Ethyl alcohol

C : CH2 = CH2 Ethylene


52. Simplest alkene (A) reacts with HCl to form compound (B).Compound (B) reacts with ammonia to form compound (C) of molecular formula C2H7N.Compound (C) undergoes carbylamine test. Identify (A), (B), and (C).

Given :

Solution :

Simplest alkene (A) means, it is ethylene. Ethylene (A) react with HCl to give form ethyl chloride (B)

CH2 = CH2 (A) + HCl → CH3CH2Cl (B)

Ethylchloride (B) reacts with ammonia to form ethylamine (C)

CH3CH2Cl (B) + NH3 → CH3CH2NH2 (C) + HCl

Result :

Compound : Formula & Name

A : CH2 = CH2 Ethylene

B : CH3CH2Cl Ethyl chloride

C : CH3CH2NH2 Ethylamine


53. A hydrocarbon C3H6 (A) reacts with HBr to form compound (B). Compound (B) reacts with aqueous potassium hydroxide to give (C) of molecular formula C3H6O.what are (A) (B) and (C). Explain the reactions.


As per molecular formula, A must be alkene ie., propene compound (A) reacts with HBr forms isopropyl bromide (B)

Isopropyl bromide (B) reacts with aq. KOH give isopropyl alcohol (C)



54. Two isomers (A) and (B) have the same molecular formula C2H4Cl2. Compound (A) reacts with aqueous KOH gives compound (C) of molecular formula C2H4O. Compound (B) reacts with aqueous KOH gives compound (D) of molecular formula C2H6O2. Identify (A),(B),(C) and (D).



Compound (A) is dihalide. So, the possible dihalide will be vicinal dihalide and gemdihalide. The possible two isomers are

Compound (A) 1, 1-Dichloro ethane on hydrolysis with aq.KOH give aldehyde (B)

Compound (B), 1, 2 - Dichloro ethane on hydrolysis with aq.KOH gives diols (D) 


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11th Chemistry : UNIT 14 : Haloalkanes and Haloarenes : Brief questions and answers: Chemistry: Haloalkanes and Haloarenes |

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11th Chemistry : UNIT 14 : Haloalkanes and Haloarenes

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