Sampling and Non-Sampling Errors: Computing standard error in simple cases - Example Solved Problems with Answer, Solution, Formula

**Computing
standard error in simple cases**

**Example 8.6**

A server channel
monitored for an hour was found to have an estimated mean of 20 transactions
transmitted per minute. The variance is known to be 4. Find the standard error.

*Solution:*

**Example 8.7**

Find the sample size for
the given standard deviation 10 and the standard error with respect of sample
mean is 3.

*Solution:*

**Example 8.8**

A die is thrown 9000
times and a throw of 3 or 4 is observed 3240 times. Find the standard error of
the proportion for an unbiased die .

*Solution:*

If the occurrence of 3
or 4 on the die is called a success, then

Sample size = 9000;
Number of Success = 3240

Sample proportion = p =
3240/9000 = 0 36.

Population proportion
(P) = Prob(getting 3 or 4 when a die is thrown)

Thus P = 0.3333 and Q =
1–P=1– 0.3333 = 0.6667

The S.E for sample
proportion is given by

Hence the standard error for sample proportion is S.E=0.00496.

**Example 8.9**

The standard deviation
of a sample of size 50 is 6.3. Determine the standard error whose population
standard deviation is 6?

*Solution:*

**Example 8.10**

A sample of 100 students
is chosen from a large group of students. The average height of these students
is 162 cm and standard deviation (S.D) is 8 cm. Obtain the standard error for
the average height of large group of students of 160 cm?

*Solution:*

Therefore the standard error for the
average height of large group of students of 160 cm is 0.8.

Tags : Example Solved Problems with Answer, Solution | Sampling and Non-Sampling Errors , 12th Business Maths and Statistics : Chapter 8 : Sampling Techniques and Statistical Inference

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12th Business Maths and Statistics : Chapter 8 : Sampling Techniques and Statistical Inference : Computing standard error in simple cases | Example Solved Problems with Answer, Solution | Sampling and Non-Sampling Errors

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