Home | | Zoology 12th Std | Molecular Genetics: Questions and Answers (Evaluation)

Book Back Important Questions Answers | Choose the Correct Answers | Short, brief Answers | Zoology - Molecular Genetics: Questions and Answers (Evaluation) | 12th Zoology : Chapter 5 : Molecular Genetics

Chapter: 12th Zoology : Chapter 5 : Molecular Genetics

Molecular Genetics: Questions and Answers (Evaluation)

Zoology : Molecular Genetics : Book Back Questions Answers: Choose the Correct Answers, Short Answers, brief Answers, Important Questions and Answers



1. Hershey and Chase experiment with bacteriophage showed that

a) Protein gets into the bacterial cells

b) DNA is the genetic material

c) DNA contains radioactive sulphur

d) Viruses undergo transformation

Answer: b) DNA is the genetic material


2. DNA and RNA are similar with respect to

a) Thymine as a nitrogen base

b) A single-stranded helix shape

c) Nucleotide containing sugars, nitrogen bases and phosphates

d) The same sequence of nucleotides for the amino acid phenyl alanine

Answer: c) Nucleotide containing sugars, nitrogen bases and phosphates


3. A mRNA molecule is produced by

a) Replication

b) Transcription

c) Duplication

d) Translation

Answer: b) Transcription


4. The total number of nitrogenous bases in human genome is estimated to be about

a) 3.5 million

b) 35000

c) 35 million

d) 3.1 billion

d) 3.1 billion


5. E. coli cell grown on 15N medium are transferred to 14N medium and allowed to grow for two generations. DNA extracted from these cells is ultra centrifuged in a cesium chloride density gradient. What density distribution of DNA would you expect in this experiment?

(a) One high and one low density band.

(b) One intermediate density band.

(c) One high and one intermediate density band.

(d) One low and one intermediate density band.

Answer: d) One low and one intermediate density band


6. What is the basis for the difference in the synthesis of the leading and lagging strand of DNA molecules?

(a) Origin of replication occurs only at the 5' end of the molecules.

(b) DNA ligase works only in the 3' → 5' direction.

(c) DNA polymerase can join new nucleotides only to the 3' end of the growing stand.

(d) Helicases and single-strand binding proteins that work at the 5' end.

Answer: c) DNA polymerase can join new nucleotides only to the 3' end of the growing stand


7. Which of the following is the correct sequence of event with reference to the central dogma?

(a) Transcription, Translation, Replication

(b) Transcription, Replication, Translation

(c) Duplication, Translation, Transcription

(d) Replication, Transcription, Translation

Answer: d) Replication, Transcription, Translation


8. Which of the following statements about DNA replication is not correct?

(a) Unwinding of DNA molecule occurs as hydrogen bonds break.

(b) Replication occurs as each base is paired with another exactly like it.

(c) Process is known as semi conservative replication because one old strand is conserved in the new molecule.

(d) Complementary base pairs are held together with hydrogen bonds.

Answer: b) Replication occurs as each base is paired with another exactly like it


9. Which of the following statements is not true about DNA replication in eukaryotes?

(a) Replication begins at a single origin of replication.

(b) Replication is bidirectional from the origins.

(c) Replication occurs at about 1 million base pairs per minute.

(d) There are numerous different bacterial chromosomes, with replication ocurring in each at the same time.

Answer: d) These are numerous different bacterial chromosomes, with replication occurring in each at the same time.


10. The first codon to be deciphered was UUU which codes for Phenylalanine.

(a) AAA, proline

(b) GGG, alanine

(c) UUU, Phenylalanine

(d)TTT, arginine


11. Meselson and Stahl’s experiment proved


(b) Transformation

(c) DNA is the genetic material

(d) Semi-conservative nature of DNA replication

Answer: d) Semi-conservative nature of DNA replication


12. Ribosomes are composed of two subunits; the smaller subunit of a ribosome has a binding site for mRNA and the larger subunit has two binding sites for two tRNAAns (mRNA, tRNA)


13. An operon is a:

(a) Protein that suppresses gene expression

(b) Protein that accelerates gene expression

(c) Cluster of structural genes with related function

(d) Gene that switched other genes on or off

Answer: c) Cluster of structural genes with related function


14. When lactose is present in the culture medium:

(a) Transcription of lac y, lac z, lac a genes occurs.

(b) Repressor is unable to bind to the operator.

(c) Repressor is able to bind to the operator.

(d) Both (a) and (b) are correct.

Answer: d) Both (a) and (b) are correct


15. Give reasons: Genetic code is ‘universal’.

The genetic code is nearly universal.

Almost all living organisms use nucleic acids and the particular triplet codon code for the same amino acid in the synthesis of protein.

Eg - In the mRNA UUU codon codes for phenyl alanine in all cells of all living organisms.

Exceptions to genetic code

1. Prokaryotes

2. Mitochondrial / Chloroplast genomes

However have more similarities than differences.


16. Name the parts marked ‘A’ and ‘B’ in the given transcription unit:

A - Promoter

B - Coding strand.


17. Differentiate - Leading stand and lagging strand

Leading strand

The replication of DNA on this strand is continuous.

DNA ligase is not required

The synthesize occur in the 5' → 3' direction only & the polarity of template strand is 3' → 5' only

Lagging strand

The replication of DNA on this strand is discontinuous in the form of fragments called okazaki - fragments.

DNA ligase enzyme is required for joining okazaki - fragments.

Here the polarity is from 5' → 3' but overall direction of template strand is 3' → 5'


18. Differentiate - Template strand and coding strand.

Template strand

It act as a template for synthesis of mRNA.

It has a sequence complementary to the mRNA.

It runs in 3' → 5' direction or polarity.

Coding strand

It does not act as template.

It has a sequence similar to the mRNA.

It runs from 5' → 3' direction or polarity


19. Mention any two ways in which single nucleotide polymorphism (SNPs) identified in human genome can bring revolutionary change in biological and medical science.

Scientists have identified 1.4 million locations in Human Genome, where SNP occur.

This findings will bring in biological & medical science revolutionary changes.

It helps to understand, predict certain diseases (Sickle cell anaemia, B thalassemia, Cystic fibrosis etc)

It also helps to predict an individuals response to certain drugs, susceptibility to environmental factors such as toxins etc.


20. State any three goals of the human genome project.

The main goals of HGP.

Identifying all the genes (approximately 30,000) of human DNA.

Determining the sequence of the 3 billion chemical base pairs that make up the human DNA.

To store these informations in data bases & improve Tools for data analysis.


21. In E.coli, three enzymes β- galactosidase, permease and transacetylase are produced in the presence of lactose. Explain why the enzymes are not synthesized in the absence of lactose.

In the Absence of lactose,


22. Distinguish between structural gene, regulatory gene and operator gene.

Promotor gene

All other genes - under the control of promoter.

They are signal sequence of DNA, where RNA polymerase binds and the transcription begins.

Operator gene

Adjacent to structural gene that control transcriptional activity of structural gene.

Regulator gene

Codes for a repressor protein, that binds to the operator, obstructing the promotor - thus transcription of the structural genes.

Structural gene

It is polycistronic - there are 3 genes (Z gene Y gene & 'a' gene)

Z gene codes for β galactosidase

Y gene codes for permease

A gene codes for transacetylase

It get transcribed into mRNA, rRNA & tRNA encodes proteins required by the cell


The promoter & Regulator gene regulate the structural genes.


23. A low level of expression of lac operon occurs at all the windows for treatment of various genetic disorders. Justify the statement.

Lactose present in the external medium can enter the bacterium only when the bacterium contain the enzyme (permease)

So, formation of permease require a low level expression of lac - operon.


24. Why the human genome project is called a mega project?


HGP – was launched in 1990 & took 13 years to complete.


HG – is about 25 times larger than the genome of any organism sequenced.

It is the 1st vertebrate genome to be completed.

HG – is said to have about 3 × 109 bp – the cost of sequencing this in US $ per bp – is 3 dollors & the total cost would be US $ 9 billion.

Data Storage & Retrieval

The data need atleast 3300 books (1000 letters & 1000 pages in each book) to store the complete information of DNA sequence from a single human cell.

We need high speed computing devices for storage, retrieval & analysis.

Bio informatics

A new area in biology encompasses the application of computing science & technology to analyse and manage the biological data.


25. From their examination of the structure of DNA, What did Watson and Crick infer about the probable mechanism of DNA replication, coding capability and mutation?

Watson & Crick, from their examination of the structure of DNA (DNA - model) - inferred that DNA replication was semi conservative replication.

The two polynucleotide strands of DNA - unwind and start separating at one end breaking the covalent hydrogen bond.

The separated single strand act as template for the synthesis of a new strand.

Daughter double helix

  |One polynucleotide strand (parental)

  |another polynucleotide strand (newly synthesised)

The two strands are complementary to each other.


26. Why tRNA is called an adapter molecule?

Francis Crick - postulated this term.

tRNA, - molecule of a cell acts as a vehicle that reads the specific codes of mRNA molecules & intum picks up the specific amino acid, according to the specific code - (from the amino acids scattered in the cytoplasm)

Hence t-RNA is also known as Adapter molecule.


27. What are the three structural differences between RNA and DNA?


Stands: Single

Sugar: Ribose sugar

Nitrogenbases: Adenine, Guanine, Uracil & Cytosine

Reactivity: More reactive Chemically & Structurally less stable

Occurence: Very little RNA occur inside the nucleus most of it is found in the cytoplasm


Stands: double (exception, some viruses)

Sugar: Deoxyribose sugar

Nitrogenbases: Adenine, Guanine, Thyamine & Cytosine

Reactivity: Less reactive Chemically & Structurally more stable

Occurence: Usually occur in the Nucleus - also in cell organelles mitochondria & chloroplast


28. Name the anticodon required to recognize the following codons: AAU, CGA, UAU, and GCA.


Anti codon UUA GCU AUA CGU


29. a) Identify the figure given below

b) Redraw the structure as a replicating fork and label the parts

c) Write the source of energy for this replication and name the enzyme involved in this process.

d) Mention the differences in the synthesis of protein, based on the polarity of the two template strands.

a) Mechanism of Replication, showing a Replication fork


Answer: A - Template Stands

B - Replication Fork

C - Leading strand

D - Lagging Strand

c) Source of energy for this replication Deoxy nucleotide triphosphate not only provide energy for the polymerization reactions but also act as substrate for the reaction.

d) The DNA consists of two complementary strands of opposite polarity.

One having polarity 5' to 3' while other having polarity 3' to 5'.

Both the strands of DNA not copied during transcription for 2 reasons.

1) If both strands act as template it would code for proteins with different amino acid sequence resulting in one segment of DNA coding for two different proteins - create complication.

2) If two RNA molecules were produced simultaneously, double stranded RNA complementary to each other would be formed. This also would prevent RNA from being translated into proteins.


30. If the coding sequence in a transcription unit is written as follows:


Write down the sequence of mRNA.



31. How is the two stage process of protein synthesis advantageous?

Yes, The synthesis of proteins takes place in two steps

  |→ Transcription &

  |→ Translation

Francis Crick - proposed the Central dogma in molecular biology

I - stage - Transcription

The information encoded in DNA should be transcribed into mRNA

II - stage - Translation

The encodes information in mRNA heads out of the cells nucleus and into the cytoplasm & The Translation machinery work here, with rRNA, mRNA, tRNA & various enzymes so, the two stage - process is essential & it is advantageous too.


32.Why did Hershey and Chase use radioactively labelled phosphorous and sulphur only? Would they have got the same result if they use radiolabelled carbon and nitrogen?

I. - Radio actively labelled carbon

If Hershey & Chase would have used radio labelled carbon - it would be found in all components of bacteria.

Carbon is found in all organic molecules

II. - Radio actively labelled Nitrogen

If they had used radio actively labelled Nitrogen, they would have seen that all the cells would be labelled in the nucleolus, in the membrane and through out the cell, also the multiplied numerous components of phage, would be also labelled -

Nitrogen is found in proteins & DNA, so Hershey & Chase wisely used radio actively labelled phosphorus (component of nucleic acids) and sulphur (component of proteins) in their experiment.


33. Explain the formation of a nucleosome.

I. Chromosome is made up of chromatin.

Chromatin is formed of a series of repeated units called Nucleosomes.

Kornberg's model for the nucleosome

In this 2 molecules of four histone proteins H2 A, H2 B, H3 & H4 are organised to form a unit of 8 molecules called Histone octomer.

The negatively charged DNA is wrapped around the positively charged histone octomer to form a structure called nucleosome.

A typical nucleosome contain 200 bp of DNA helix.

DNA connecting two adjacent nucleosome are called linker DNA, (H1) exposed to enzymes

II. The DNA makes two complete turns around the histone octomer, and sealed off by an H1 molecule.

Chromatin lacking H1-, nucleosomes are thread like stained bodies present in Nucleus (look like beads on a string - (under EM)

H1 of one nucleosome can interact with H1 of another - resulting in further folding of the Chromatin fibre.

The Chromatin is packed to form a solenoid structure of 30 nm diameter (having six nucleosome per turn)

Stabilized by interaction between different H1 molecules.

DNA - is a solenoid & packed about 40 folds.

This further supercoils & forms chromatin fibre.

Chromatin fibre → Further coils & condenses to form chromatids.

Chromatids → Further condenses at metaphase stage of cell division to form chromosomes.

III. NHC - Proteins

The Non histone chromosomal proteins are required for a higher level packaging.

Euchromatin - regions of chromatin loosely packed and transcriptionally active.

Hetero chromatin - regions of chromatin densely packed (Stained darkly), and

transcriptionally in active.


34. It is established that RNA is the first genetic material. Justify giving reasons.

Amount: A typical cell contains, about ten times as much as RNA as DNA

Various roles : Through various researchers the essential life processes such as metabolism, translator splicing etc.

Evidences : Frankel - Conrat & Singer (1957)

Said RNA - the genetic material in TMV - and separated it from the protein of TMV virus.

Leslie Orgel, Francis Brick & Carl Woese, these three

Molecular biologists (1980s) - proposed RNA world - as the first stage in evolution of life - when RNA catalysed all molecules necessary for survival & replication.

Walter Gilbert (1986) - First used the term RNA World

 RNA has ability act as

  |→ Genetic material

 |→ Catalyst

Catalytic RNA - is ribozyme

RNA, being a catalyst was reactive & hence unstable

DNA has evolved from RNA - with chemical modifications.

Tags : Book Back Important Questions Answers | Choose the Correct Answers | Short, brief Answers | Zoology , 12th Zoology : Chapter 5 : Molecular Genetics
Study Material, Lecturing Notes, Assignment, Reference, Wiki description explanation, brief detail
12th Zoology : Chapter 5 : Molecular Genetics : Molecular Genetics: Questions and Answers (Evaluation) | Book Back Important Questions Answers | Choose the Correct Answers | Short, brief Answers | Zoology

Privacy Policy, Terms and Conditions, DMCA Policy and Compliant

Copyright © 2018-2024 BrainKart.com; All Rights Reserved. Developed by Therithal info, Chennai.