6th Maths : Term 1 Unit 1 : Numbers : Text Book Back Exercises Questions with Answers, Solution

__Exercise
1.4__

** **

**1.
Fill in the blanks.**

**(i)
The nearest 100 of 843 is ___________. **

**(ii)
The nearest 1000 of 756 is ___________. **

**(iii)
The nearest 10000 of 85654 is ___________. **

** **

**2.
Say True or False.**

**(i)
8567 is rounded off as 8600 to the nearest 10.**

**(ii)
139 is rounded off as 100 to the nearest 100.**

**(iii)
1,70,51,972 is rounded off as 1,70,00,000 to the nearest lakh.**

** **

**3.
Round off the following to the given nearest place.**

**(i)
4,065; hundred**

**Solution: 4, 065; hundred**

Compare tenth place 6 > 5; Add ‘1’ to hundredth place and
make tenth and oneth place as zero.

4,__0__65; hundred = 6 > 5

= 4100

**(ii)
44,555; thousand**

**Solution:**

4** 4**,555 = 5 = 5 → 45,000

**(iii)
86,943; ten thousand**

**Solution:**

** 8**6,943 = 6 > 5 → 90,000

**(iv)
50,81,739; lakh**

**Solution:**

5** 0**,81,739 = 8 > 5 → 51,00,000

**(v)
33,75,98,482; ten crore**

**Solution:**

** 3**3,75,98,482 = 3 < 5 → 30,00,00,000

** **

**4.
Estimate the sum of 157826 and 32469 rounded off to the nearest ten thousand .**

**Solution:**

Sum of 157826 and 32469

Actual:

1,57,826

32,469

__1,90,295__

157826 + 32469 = 1,90,295

Estimated sum = 1,60,000

nearest ten thousand = 30,000

__1,90,000__

Hence Estimated sum of 157826 and 32469 = 1,90,000

** **

**5.
Estimate by rounding off each number to the nearest hundred.**

**(i)
8074 + 4178 **

**(ii)
1768977 + 130589**

**Solution:**

**(i) 8074 + 4178 **

**Estimate :**

nearest hundred = 8100 + 4200

= 12,300

Hence estimated of 8074 + 4178 = 12,300

**(ii) 1768977 + 130589 **

**Estimate :**

nearest hundred = 1768977 + 130589

= 1899600

Hence estimated of 1768977 + 130589 = 1899600

** **

**6.
The population of a city was 43,43,645 in the year 2001 and 46,81,087 in the year
2011. Estimate the increase in population by rounding off to the nearest thousand.**

**Solution:**

Population of city in 2001 = 43,43,645

in 2011 = 46,81,087

Estimate increase in population nearest to thousand is

Population of city in 2011 = 46,81,000

in 2001 = 43,44,000

**3,37,000**

Increase in population between 2011 to 2001 is 3,37,000

** **

__Objective
Type Questions__

** **

**7.
The number which on rounding off to the nearest thousand gives 11000 is**

**(a)
10345 **

**(b)
10855 **

**(c)
11799**

**(d)
10056**

**Answer:** (b) 10855

** **

**8.
The estimation to the nearest hundred of 76812 is**

**(a)
77000**

**(b)
76000 **

**(c)
76800 **

**(d)
76900**

**Answer:** (c) 76800

** **

**9.
The number 9785764 is rounded off to the nearest lakh as**

**(a)
9800000 **

**(b)
9786000 **

**(c)
9795600 **

**(d)
9795000**

**Answer:** (a) 9800000

** **

**10.
The estimated difference of 167826 and 2765 rounded off to the nearest thousand
is**

**(a)
180000 **

**(b)
165000 **

**(c)
140000**

** (d) 155000**

**Answer:** (b) 165000

** **

__Answers:__

__Exercise 1.4__

**1) (i) 800 (ii) 1000 (iii) 90,000 **

**2) (i) False (ii) True (iii) False **

**3) (i) 4100 (ii) 45,000 (iii) 90,000 (iv) 51,00,000 (v)
30,00,00,000**

**4) 1,90,000**

**5) (i) 12,300 (ii) 18,99,600**

**6) 3,37,000**

**7) (b) 10855**

**8) (c) 76800**

**9) (a) 9800000**

**10) (b) 165000**

Tags : Questions with Answers, Solution | Numbers | Term 1 Chapter 1 | 6th Maths , 6th Maths : Term 1 Unit 1 : Numbers

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6th Maths : Term 1 Unit 1 : Numbers : Exercise 1.4 | Questions with Answers, Solution | Numbers | Term 1 Chapter 1 | 6th Maths

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