Consider a parallel plate capacitor which is maintained at potential of 200 V. If the separation distance between the plates of the capacitor and area of the plates are 1 and 20 cm2. Calculate the displacement current for the time in µs.
Potential difference between the plates of the capacitor, V = 200 V
The distance between the plates,
d = 1 mm = 1 × 10-3 m
Area of the plates of the capacitor,
A = 20 cm2 = 20 × 10-4 m2
Time is given in micro-second, µs = 10-6 s
Displacement current
But electric field, E = V/d
Therefore,
= 35400 ×10−7 = 3 .5 mA
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