Problem 1
The radius of curvature of a spherical mirror is 20 cm. Find its focal length.
Solution
Radius of curvature = 20 cm
Focal length (f) = Radius of curvature / 2
= R/2 = 20/2 = 10 cm
Problem 2
Focal length of a spherical mirror is 7 cm. What is its radius of curvature?
Solution
Radius of curvature (R) = 2 × Focal length
= 2 × 7 = 14 cm
Problem 3
If two plane mirrors are inclined to each other at an angle of 90°, find the number of images formed.
Solution
Angle of inclination = 90°
Number of umber of images formed = [360°/θ] – 1
= [360°90°] –1= 4-1=3
Problem 4
Speed of light in air is 3 × 108 m s-1 and the speed of light in a medium is 2 ×108 ms-1. Find the refractive index of the medium with respect to air.
Solution
Refractive index (μ) = Speed of light in air (c) / Speed of light in the medium (v)
μ = 3×108 / 2×108 = 1.5
Problem 5
Refractive index of water is 4/3 and the refractive index of glass is 3/2. Find the refractive index of glass with respect to the refractive index of water.
Solution
wμg = Refractive index of glass / Refractive index of water
= (3/2) / (4/3) = 9/8 = 1.125
1. The radius of curvature of a spherical mirror is 25 cm. Find its focal length.
Answer:
Given : Radius of curvature = 25 cm
To find : f = ?
Solution : f = R/2 = 25/2
f = 12.5 cm
2. If two plane mirrors are inclined to each other at an angle of 45°, find the number of images formed.
Answer:
Given : Angle of inclination = 45o
To find : Number of images formed = [ 360o / angle ] − 1
Solution :
= [ 360o / 45o ] −1
= 8 – 1 = 7 images
3. Speed of light in air is 3 × 108 m s–1 and the refractive index of a medium is 1. 5. Find the speed of light in the medium.
Answer:
Given : Speed of light in air c = 3 × 108 ms-1
Refractive index of a medium μ = 1.5
To find : Speed of light in medium v = ?
Formula : μ= c/v
Solution : 1.5 = [ 3 × 108 ] / v
V = [3×108] / 1.5
v = 2 × 108 ms-1
Speed of light in medium v = 2 × 108 ms-1
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