Questions with Answers, Solution | Geometry | Term 1 Chapter 5 | 7th Maths - Exercise 5.4 (Construction of angle bisector of an angle) | 7th Maths : Term 1 Unit 5 : Geometry
Chapter: 7th Maths : Term 1 Unit 5 : Geometry
Exercise 5.4 (Construction of angle bisector of an angle)
Exercise 5.4
1.
Construct the following angles using protractor and draw a bisector to each of the
angle using ruler and compass.
(a)
60°
(b)
100°
(c)
90°
(d)
48°
(e)
110°
(a) 60o
Step 1 : Draw the given angle ∠ABC = 60° using protractor.
Step 2 : With B as center and convenient radius, draw an arc to cut BA
and BC at E and F respectively.
Step 3 : With the same radius and E as center draw an arc in the interior
of ∠ABC and another arc with F as center to cut the previous arc at
G.
Step 4 : Join BG. BG is the required bisector of the given angle ∠ABC.
(b) 100°
Step 1 : Draw the given angle ∠ABC =100° using protractor.
Step 2 : With B as center and convenient radius, draw an arc to cut BA
and BC at E and F respectively.
Step 3 : With the same radius and E as center draw an arc in the interior
of ∠ABC and another arc with F as center to cut the previous arc at
G.
Step 4 : Join BG. BG is the required bisector of the given angle ∠ABC.
(c) 90°
Step 1 : Draw the given angle ∠ABC = 90° using protractor.
Step 2 : With B as center and convenient radius, draw an arc to cut BA
and BC at E and F respectively.
Step 3 : With the same radius and E as center draw an arc in the interior
of ∠ABC and another arc with F as center to cut the previous arc at
G.
Step 4 : Join BG. BG is the required bisector of the given angle ∠ABC.
(d) 48°
Step 1 : Draw the given angle ∠ABC = 48° using protractor.
Step 2 : With B as center and convenient radius, draw an arc to cut BA
and BC at E and F respectively.
Step 3 : With the same radius and E as center draw an arc in the interior
of ∠ABC and another arc with F as center to cut the previous arc at
G.
Step 4 : Join BG. BG is the required bisector of the given angle ∠ABC.
(e) 110°
Step 1 : Draw the given angle ∠ABC =110° using protractor.
Step 2 : With B as center and convenient radius, draw an arc to cut BA
and BC at E and F respectively.
Step 3 : With the same radius and E as center draw an arc in the interior
of ∠ABC and another arc with F as center to cut the previous arc at
G.
Step 4 : Join BG. BG is the required bisector of the given angle ∠ABC.
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