7th Maths : Term 1 Unit 5 : Geometry : Construction of angle bisector of an angle : Text Book Back Exercises Questions with Answers, Solution :
Construct the following angles using protractor and draw a bisector to each of the angle using ruler and compass.

**Exercise 5.4**

**1.
Construct the following angles using protractor and draw a bisector to each of the
angle using ruler and compass.**

**(a)
60° **

**(b)
100° **

**(c)
90° **

**(d)
48° **

**(e)
110°**

**(a) 60 ^{o}**

**Step 1 :** Draw the given angle ∠ABC = 60° using protractor.

**Step 2 :** With B as center and convenient radius, draw an arc to cut BA
and BC at E and F respectively.

**Step 3 :** With the same radius and E as center draw an arc in the interior
of ∠ABC and another arc with F as center to cut the previous arc at
G.

**Step 4 :** Join BG. BG is the required bisector of the given angle ∠ABC.

**(b) 100°**

**Step 1 :** Draw the given angle ∠ABC =100° using protractor.

**Step 2 :** With B as center and convenient radius, draw an arc to cut BA
and BC at E and F respectively.

**Step 3 :** With the same radius and E as center draw an arc in the interior
of ∠ABC and another arc with F as center to cut the previous arc at
G.

**Step 4 :** Join BG. BG is the required bisector of the given angle ∠ABC.

** **

**(c) 90°**

**Step 1 :** Draw the given angle ∠ABC = 90° using protractor.

**Step 2 :** With B as center and convenient radius, draw an arc to cut BA
and BC at E and F respectively.

**Step 3 :** With the same radius and E as center draw an arc in the interior
of ∠ABC and another arc with F as center to cut the previous arc at
G.

**Step 4 :** Join BG. BG is the required bisector of the given angle ∠ABC.

** **

**(d) 48°**

**Step 1 :** Draw the given angle ∠ABC = 48° using protractor.

**Step 2 :** With B as center and convenient radius, draw an arc to cut BA
and BC at E and F respectively.

**Step 3 :** With the same radius and E as center draw an arc in the interior
of ∠ABC and another arc with F as center to cut the previous arc at
G.

**Step 4 :** Join BG. BG is the required bisector of the given angle ∠ABC.

** **

**(e) 110°**

**Step 1 :** Draw the given angle ∠ABC =110° using protractor.

**Step 2 :** With B as center and convenient radius, draw an arc to cut BA
and BC at E and F respectively.

**Step 3 :** With the same radius and E as center draw an arc in the interior
of ∠ABC and another arc with F as center to cut the previous arc at
G.

**Step 4 :** Join BG. BG is the required bisector of the given angle ∠ABC.

Tags : Questions with Answers, Solution | Geometry | Term 1 Chapter 5 | 7th Maths , 7th Maths : Term 1 Unit 5 : Geometry

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7th Maths : Term 1 Unit 5 : Geometry : Exercise 5.4 (Construction of angle bisector of an angle) | Questions with Answers, Solution | Geometry | Term 1 Chapter 5 | 7th Maths

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