These are perpendicular lines. In both the cases the perpendicular line l divides both the line segments into two equal parts. This line is called perpendicular bisector of the line segment.

**Construction
of perpendicular bisector of a line segment**

In earlier class, we learnt about perpendicular
lines. Observe the Fig.5.24.

These are perpendicular lines. In both the cases
the perpendicular line *l* divides both the line segments into two equal parts. This line
is called perpendicular bisector of the line segment. So, a perpendicular line which divides a line segment into two
equal parts is a perpendicular
bisector of the given line
segment.

Now we are going to learn, how to construct a perpendicular
bisector to a given line segment.

__Example 5.11 __

Construct a perpendicular bisector of
the line segment** ***AB*** **= 6 *cm*.

**Step 1: **Draw a line. Mark two points** ***A*** **and** ***B*** **on it so that *AB *= 6 *cm*.

**Step 2: **Using compass with** ***A*** **as center and radius more than half
of the length of *AB,* draw two arcs of same length, one above *AB* and one below *AB*.

**Step 3:** With the same radius and *B* as center draw two arcs to cut the arcs drawn in step 2. Mark the points
of intersection of the arcs as *C* and *D*

**Step 4: **Join** ***C*** **and** ***D*.** ***CD*** **will intersect** ***AB*. Mark the point of intersection as *O*

*CD *is the required perpendicular bisector of* AB*.

Measure ∠*AOC*. Measure the length of *AO* and *OB*. What do you observe?

**Think**

1. What will happen if the radius of
the arc is less than half of *AB*?

Tags : Geometry | Term 1 Chapter 5 | 7th Maths , 7th Maths : Term 1 Unit 5 : Geometry

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7th Maths : Term 1 Unit 5 : Geometry : Construction of perpendicular bisector of a line segment | Geometry | Term 1 Chapter 5 | 7th Maths

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