Bernoulliâ€™s formula for integration of product of two functions is below

**Bernoulliâ€™s
Formula**

The
evaluation of an indefinite integral of the form âˆ«*u* (*x*) *v*
( *x*)*dx* becomes very simple, when *u
*is a polynomial function of *x*
(that is, *u* ( *x*) = *a*_{0}
*x ^{n}* +

Proceeding
in this way, we get

âˆ« *uvdx* = *uv*_{(1)} âˆ’ *u* ^{(1)}*v*_{( 2)} + *u* ^{( 2)}*v*_{( 3)} âˆ’ *u* ^{(3)}*v*_{( 4)} + .

The
above result is called the **Bernoulliâ€™s formula for integration of product of two
functions.**

**Note**

Since *u* is a polynomial function of *x* , the successive derivative *u*( * ^{m}*)
will be zero for some positive integer

** **

**Example 9.31**

Evaluate
^{Ï€}âˆ«_{0} *x*^{2}
cos *nx dx* , where *n* is a positive integer.

**Solution**

Taking *u* = *x*^{2}
and *v* = cos *nx* , and applying the Bernoulliâ€™s formula, we get

** **

Evaluate
: ^{1}âˆ«_{0} e^{âˆ’}^{2x} (1 + *x*
âˆ’
2*x*^{3} ) *dx* .

Taking *u* = 1 + *x*
âˆ’
2*x*^{3} and *v* = e^{âˆ’}^{2x} , and applying the Bernoulliâ€™s formula, we get

I = ^{1}âˆ«_{0} e^{âˆ’}^{2x} (1+ *x*
âˆ’
2*x*^{3} ) *dx*

** **

**Example 9.33**

Evaluate
: ^{2}^{Ï€}âˆ«_{0} *x*^{2}
sin *nx dx* , where *n* is a positive integer.

**Solution**

Taking *u* = *x*^{2}
and *v* = sin *nx* , and applying the Bernoulliâ€™s formula, we get

** **

**Example 9.34**

Evaluate
: ^{1}âˆ«_{âˆ’}_{1} e^{âˆ’ Î»}* ^{x}* (1 âˆ’

Taking *u* = 1âˆ’ *x*^{2}
and *v* = e^{âˆ’Î»} * ^{x}*
, and applying the Bernoulliâ€™s formula, we get

Tags : Applications of Integration , 12th Maths : UNIT 9 : Applications of Integration

Study Material, Lecturing Notes, Assignment, Reference, Wiki description explanation, brief detail

12th Maths : UNIT 9 : Applications of Integration : Bernoulliâ€™s Formula | Applications of Integration

**Related Topics **

Privacy Policy, Terms and Conditions, DMCA Policy and Compliant

Copyright Â© 2018-2023 BrainKart.com; All Rights Reserved. Developed by Therithal info, Chennai.