7th Maths : Term 1 Unit 3 : Algebra : Simple linear equations : Exercise 3.3 : Fill in the blanks, Say true or false, Find the value of the following, Objective type questions, Text Book Back Exercises Questions with Answers, Solution

**Exercise
3.3**

**1. Fill in the blanks.**

(i) An expression equated
to another expression is called __equation.__

(ii) If *a* = 5, the value of 2*a* + 5 is __2(5) + 5 = 10 + 5 = 15.__

(iii) The sum of twice
and four times of the variable *x* is __2 x and 4x.__

**2. Say True or False.**

(i) Every algebraic
expression is an equation**(False)**

(ii) The expression
7*x* + 1 can not be reduced without knowing the value of *x*. **(True)**

(iii) To add two like terms, its coefficients can
be added.**(True)**

**3.
Solve:**

**(i)
***x*** + 5 = 8 (ii) p − 3 = 7 (iii) 2***x*** = 30 (iv) m/6 = 5 (v) 7x + 10 = 80**

**(i) x + 5 = 8**

x + 5 – 5 = 8 – 5

**x = 3**

**(ii) p – 3 =7**

*p* – 3 + 3 = 7 + 3

*p*** = 10**

**(iii) 2 x = 20 **

2*x* / 2 = 20 / 2

*x *= 10

**(iv) m / 6 = 5**

[*m*/6] × 6 = 5 × 6

*m ***= 30**

**(v) 7 x + 10 = 80**

7*x* + 10 – 10 = 80 – 10

7*x *= 70

7*x* / 7 = 70 / 7

*x ***= 10**

** **

**4.
What should be added to 3***x*** + 6***y*** to get 5***x*** + 8***y***?**

5*x* + 8*y* – (3*x* + 6*y*)

5*x* + 8*y *– 3*x*
– 6y

5*x* – 3*x* + 8*y*–
6*y*

(5 – 3) *x* + (8 – 6)*y *

2*x* + 2*y*

2*x* + 2*y *should be added to 3*x* + 6*y*
to get 5*x* + 8*y*

** **

**5. Nine added to thrice a whole number gives 45.
Find the number.**

Let the whole number be *x*

3*x* + 9 = 45

3*x *+ 9 – 9 = 45 – 9

3*x* = 36

3 / 3 *x =* 36 / 3

** x =
12**

** **

**6. Find two consecutive odd numbers whose sum is
200.**

Let the two consecutive odd numbers

be *x, x* + 2

Their sum *x + x* + 2 =
200

2*x* + 2 = 200

2*x* + 2 – 2 = 200 – 2

2*x* = 198

2x / 2 = 198 / 2

*x* = 99

*x *+ 2 = 99+ 2 =101

**The two consecutive
odd numbers are 99, 101.**

** **

**7.
The taxi charges in a city comprise of a fixed charge of ****₹**** 100 for 5 kms
and ****₹**** 16 per
km for every additional km. If the amount paid at the end of the trip was **

The distance travelled =* x*
km

Fixed charge for 5 *km* =
₹ 100

Remaining distance = (*x*
– 5) km

Charge for every additional *km*
= ₹ 16

Charge for (*x* – 5)km =
₹ (x – 5) 16

Given (*x –* 5) 16 = ₹ 740
– 100

= ₹ 640

(*x* – 5)* *x 16 / 16 = 640 /
16 = 40

* x *– 5 = 40

* x*
– 5 + 5 = 40 + 5

* x *= 45

**The distance
travelled = 45 km**

** **

__Objective
type questions__

**8. The generalization of the number pattern 3, 6,
9, 12,… is**

(i) *n*

(ii) 2*n*

(iii) 3*n*

(iv) 4*n*

*Answer :***(iii) 3 n**

**9.
The solution of 3***x*** + 5 = ***x*** + 9 is**

(i) 2

(ii) 3

(iii) 5

(iv) 4

*Answer :***(i) 2**

**10.
The equation ***y ***+ 1 = 0 is true
only when*** y ***is**

(i) 0

(ii) − 1

(iii) 1

(iv) − 2

*Answer :***(ii) – 1**

** **

**ANSWERS**

**EXERCISE-3.3 **

1. (i) equation (ii) 15 (iii) 6*x*

2. (i) False (ii) True (iii) True

3. (i)* x *= 3 (ii) *p* = 10 (iii)* x *= 15 (iv)* m *= 30 (v)* x *= 10

4. 2*x*+2*y*

5.* x *= 12

6. 99 and 101

7.* x *= 45*km*

** Objective type questions **

8. (iii) 3*n*

9. (i) 2

10. (ii) −1

Tags : Questions with Answers, Solution | Algebra | Term 1 Chapter 3 | 7th Maths , 7th Maths : Term 1 Unit 3 : Algebra

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7th Maths : Term 1 Unit 3 : Algebra : Exercise 3.3 (Simple linear equations) | Questions with Answers, Solution | Algebra | Term 1 Chapter 3 | 7th Maths

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