Solved
Problems:
1. A trial carried out in a four stroke single
cylinder gas engine gave the following results. Cylinder dia=300 mm, Engine
stroke=500mm, Clearance volume=6750cc, Explosions per minute=100 Pmax KN/m2 = 765 Net work load on the brake=190kg
Brake dia=1.5m Rope dia=2 5mm, Speed of the engine=240rpm, Gas used=30 m3/kghr , Calorific value of gas=2 0515 KJ/ m3
. Determine compression rat io, mechanical efficiency, indicated thermal
efficiency, air standard efficiency, relative efficiency, assume r=1.4
GIVEN DATA:-
Dia of
cylind er (d)=300mm=0.3m
Engine
stroke(l)=500mm=0.5m
Clearance
volume(vc)=6750/1003=6.75 m3
Explosions
pe r minute(n)=100/minute=i.67/sec
Pmin=765
KN /m2
Brake
drum dia(D1)=1.5m
Rope
dia(d1)= 0.025m
Work load
on the brake(w)=190kg=1.86KN
TO FIND:-
Compression
rati o (r)
Mechanical
efficiency (ηmech)
Indicated
thermal efficiency (ηit)
Air
standard efficiency (ηair)
Relative
efficiency (ηrel)
2. The following observat ions are recorded during a test on a
four-stroke petrol engine, F.C = 3000 of fuel in 12sec, speed of the engine is
2500rpm, B.P = 20KW, Air intake orifice diameter = 35 mm,Pressure across the
orifice = 140mm of water coefficient of discharge of orifice = 0.6 , piston
diameter = 150mm, stroke length = 100 mm, Density of the fuel = 0.85gm/cc , r=6
.5, Cv of fuel = 42000KJ/Kg, Barometric pressure = 760mm of Hg , Room
temperature = 24oc
Determine:
(i) Volumetric
ef ficiency on the air basis alone
(ii)
Air-fuel ratio
(iii)
The brake mean effective pressure
(iv)
The relative efficiency on the brake thermal
efficiency
Given
data:
Fuel c onsumption = 30cc in 12sec
Speed (N) = 2500/60 rps
Brake power = 20KW
Orifice diameter (do) = 0.035 m
Pressure across the orifice (Po) = 140mm of water
Coefficient of discharge (Cd) = 0.6
Piston diameter (d) = 150mm =
0.15m Stroke length (l) = 0.1m
Density of fuel (ρ) =
0.85gm/ cc Compression ratio (r) = 6.5 Room temperature (Ta) = 297 K
Barometric pressure = 760mm of Hg
= 101.325KK/m2= 10.34m of water To Find:
(i)
Volumet ric efficiency on the air basis alone
(ii)
Air-fuel ratio
(iii)
The brake mean effective pressure
(iv)
The relative efficiency on the brake thermal
efficiency
Solution:
Relative efficiency on brake thermal efficiency basis (ηrel) =
ηBT/ ηair
=
0.22409/0.52703
ηrel
=
42.52%
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