Home | | **Business Maths 12th Std** | Echelon form and finding the rank of the matrix (upto the order of 3×4)

(i) Every row of A which has all its entries 0 occurs below every row which has a non-zero entry.
(ii) The number of zeros before the first non-zero element in a row is less then the number of such zeros in the next row.

**Echelon form and finding the rank of the
matrix (upto the order of 3×4)**

A matrix *A* of order *m* × *n* is said to be in echelon form if

(i) Every row of *A* which has all its entries 0 occurs below
every row which has a non-zero entry.

(ii) The number of zeros before the first non-zero element in a
row is less then the number of such zeros in the next row.

**Example 1.6**

Find the rank of the matrix A=

*Solution :*

The order of *A* is 3 ×
3.

∴* ρ*(*A*)* *≤* *3.

Let us transform the matrix *A* to an echelon form by using
elementary transformations.

The number of non zero rows is 2

∴Rank of *A is* 2.

ρ (*A*)* *=* *2.

**Note**

A row having atleast one non -zero element is called as non-zero
row.

**Example 1.7**

Find the rank of the matrix A=

*Solution:*

The order of *A* is 3 ×
4.

∴* ρ *(*A*)≤3.

Let us transform the matrix *A* to an echelon form

The number of non zero rows is 3. ∴ ρ(*A*) =3.

**Example 1.8**

Find the rank of the matrix A=

*Solution:*

The order of *A* is 3 ×
4.

∴* ρ*(*A*)* *≤* *3.

Let us transform the matrix *A* to an echelon form

The number of non zero rows is 3.

∴* ρ *(*A*)* *=3.

We have already studied , how to solve two simultaneous linear
equations by matrix inversion method.

**Recall**

Linear equations can be written in matrix form AX=B, then the
solution is *X* = *A*^{−}^{1}*B* , provided |A| ≠0

Consider a system of linear equations with two variables,

ax + by + h

cx + dy + k (1)

Where a, b, c, d, h and k are real constants and neither a and b
nor c and d are both zero.

For any tow given lines *L*_{1} and *L*_{2},
one and only one of the following may occur.

*L*_{1}* *and* L*_{2}* *intersect at exactly one point

*L*_{1}* *and* L*_{2}* *are coincident

*L*_{1}* *and* L*_{2}* *are parallel and distinct.

(see Fig 1.1) In the first case, the system has a unique solution
corresponding to the single point of intersection of the two lines.

In the second case, the system has infinitely many solutions
corresponding to the points lying on the same line

Finally in the third case, the system has no solution because the
two lines do not intersect.

Let us illustrate each of these possibilities by considering some
specific examples.

Consider the system 2*x* −
*y* = 1, 3*x* + 2 *y* = 12 which represents two
lines intersecting at (2, 3) i.e (2, 3) lies on both lines. So the equations
are consistent and have unique solution.

Consider the system 2*x* −
*y* = 1, 6*x* − 3*y* = 3 which represents two
coincident lines. We find that any point on the line is a solution. The
equations are consistent and have infinite sets of solutions such as (0, −1), (1, 1) and so on.
Such a system is said to be dependent.

Consider the system 2*x* −
*y* = 1, 6*x* − 3*y* = 12 which represents two
parallel straight lines. The equations are inconsistent and have no solution.

A linear system composed of three linear equations with three
variables *x, y* and *z* has the general form

a_{1} x + b_{1} y + c_{1} z = d_{1}

a_{2} x + b_{2}y + c_{2}z = d_{2} (2)

a_{3} x + b_{3} y + c_{3} z = d_{3}

A linear equation *ax* +
*by* + *cz* = *d* (*a*, *b*
and *c* not all equal to zero) in three variables represents a plane in
three dimensional space. Thus, each equation in system (2) represents a plane
in three dimensional space, and the solution(s) of the system is precisely the
point(s) of intersection of the three planes defined by the three linear equations
that make up the system. This system has one and only one solution, infinitely
many solutions, or no solution, depending on whether and how the planes
intersect one another. Figure 1.2 illustrates each of these possibilities.

In Figure 1.2(a), the three planes intersect at a point
corresponding to the situation in which system (2) has a unique solution.

Figure 1.2 (b) depicts a situation in which there are infinitely
many solutions to the system. Here the three planes intersect along a line, and
the solutions are represented by the infinitely many points lying on this line.

In Figure 1.2 (c), the three planes are parallel and distinct, so
there is no point in common to all three planes; system (2) has no solution in
this case.

**Note**

Every system of linear equations has no solution, or has exactly
one solution or has infinitely many
solutions.

An arbitrary system of ‘*m*’ linear equations in ‘*n*’
unknowns can be written as

*a*_{11}* x*_{1}* *+* a *_{12}* x*_{2}* *+* *...* *+* a*_{1n}* x _{n} *=

*a*_{21}* x*_{1}* *+* a *_{22}* x*_{2}* *+* *...* *+* a*_{2n}* x _{n} *=

*. . … .
.*

*. . … .
.*

*. . … .
.*

*a _{m}*

where *x*_{1}, *x*_{2},.., *x _{n}*
are the unknowns and the subscripted

A system of ‘*m*’ linear equations in ‘*n*’ unknowns can
be abbreviated by writing only the rectangular array of numbers.

This is called the augmented matrix for the system and is the coefficient matrix.

Consider the following system of equations

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12th Business Maths and Statistics : Chapter 1 : Applications of Matrices and Determinants : Echelon form and finding the rank of the matrix (upto the order of 3×4) |

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