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# Degree of Expression

Let us recall about algebraic expression which we have studied earlier.

Degree of Expression

Let us recall about algebraic expression which we have studied earlier.

1. Recap of Algebraic expression

We have learnt that while constructing an algebraic expression, we use mathematical operators like addition, subtraction, multiplication and division to combine variables and constants.

Now, we have learnt about exponents. Note that exponential notations also can be used in the construction of Algebraic expressions.

Let us recall some basic concepts about expressions.

Consider the expression 2x + 3 , which is obtained by multiplying the variable x with the constant 2 and then adding the constant 3 to the product.

This expression is binomial as it contains two terms. The term 2x is a variable term and 3 is a constant term. 2 is the co-efficient of x.

The terms with same variables are called like terms. For example, –7x, 2x and 5x are like terms. But, term with different variables are called unlike terms. For example, 2x , 7 y are unlike terms.

We can add or subtract like terms only. We know that 2x + 5x = 7x . But, when we add unlike terms, it results in new expression. For example, 2x and 5y are unlike terms, thus resulting in new expression 2x + 5y .

2. Degree of Expressions

To know the degree of an expression, first let us try to understand the degree of a variable by relating it with the exponents of numbers. Let us consider the square numbers. They have different base and same exponents.

The geometrical representation of square numbers are given below. In general, if we consider the side of a square as a variable ‘x’ then its area will be x × x sq. units. This can be denoted as ‘x2’. Thus we have an algebraic expression with exponent notation. If we consider the term x2 as a monomial expression, the highest power of the expression is its exponent, that is 2.

Similarly, when length ‘lunits and breadth ‘bunits are variables of a rectangle, then its area is l × b = lb sq. units. We can consider lb as a term in an algebraic expression, where l and b are factors of lb.

The highest power of the expression lb is also 2, as we have to add up the powers of the variable factors.

Note

(i) When no exponent is explicitly shown in a variable of a term, it is understood to be 1. For example, 11p = 11p1 .

(ii) For an expression in x, if the terms of the expressions are in descending powers of x and the like terms are added, then we say that it is in the standard form.

For example, x4 3x3 + 5x2 7x + 9 is in the standard form. It is easier to find the highest power term when the expression is in standard form. Highest power of this expression is 4.

(iii) The highest degree term of an algebraic expression is called as leading term.

Let us consider an algebraic expression: x3 3x2 + 4 .

The terms of the above expression are x3 , 3x2 and 4. Exponent of the term x3 is 3 and 3x2 is 2.

Thus, the term x3 has the highest exponent, that is 3.

Now, consider the expression, 3x4 4x3 y 2 + 8xy + 7 .

Take each term and check its power. In 3x4 , exponent is 4, hence its degree is 4. In 4x 3 y2 , the sum of powers of x and y is 5, hence its degree is 5. In 8xy , the sum of powers is 2.

Therefore, the term with highest power in the above expression is 4x 3 y2 and its power is 5, which is called as degree of this expression.

The term(s) containing the highest power of the variables in an expression is called the degree of expression.

The degree of any term in an expression can only be a positive integer. Also, degree of expression doesn’t depend on the number of terms, but on the power of variables in the individual terms. The degree of constant term is 0.

Try these

1. Complete the following table:  2. Identify the like terms from the following:

(i) 2x2 y, 2xy2 , 3xy2 , 14x2 y, 7 yx

Like terms: 2x2y, 14x2y, 2xy2, 3xy2

(ii) 3x3 y2 , y 3x, y3x2 , y 3x, 3y 3x

Like terms: y3x, – y3x, 3y3x

(iii) 11pq, pq, 11pqr , 11pq , pq

Like terms: 11 pq, –pq, –11pq, pq

Example 3.14

Find the degree of the following expressions.

(i) x5

(ii) 3p3 q2

(iii) 4xy2 z3

(iv) 12xyz 3x3 y2z + z8

(v) 3a3b4 16c6 + 9b2c5 + 7

Solution

(i) In x5 , the exponent is 5. Thus, the degree of the expression is 5.

(ii) In 3p3q2 , the sum of powers of p and q is 5 (that is, 3+2). Thus, the degree of the expression is 5.

(iii) In 4xy2 z3 , the sum of powers of x, y and z is 6 (that is, 1+2+3). Thus, the degree of the expression is 6.

(iv) The terms of the given expression are 12xyz, 3x3 y2z, z8

Degree of each of the terms: 3, 6, 8

Terms with highest degree: z8 .

Therefore, degree of the expression is 8.

(v) The terms of the given expression are 3a3b4 , 16c6 , 9b2c5 , 7

Degree of each of the terms: 7, 6, 7, 0

Terms with highest degree: 3a3b4 ,9b2 c5

Therefore, degree of the expression is 7.

Example 3.15

Add the expressions 4x2 + 3xy + 9 y2 and 2x2 9xy + 6 y2 and find the degree.

Solution

This can be written as (4x2 + 3xy + 9 y2 ) + (2x2 9xy + 6 y2 )

Let us group the like terms, thus we have

( 4x2 + 2x2 )+ ( 3xy 9xy) + ( 9 y2 + 6 y2 ) = x2 ( 4 + 2) + xy ( 3 9) + y2 ( 9 + 6)

=6x2 6xy + 15y2

Thus, the degree of the expression is 2.

Example 3.16

Subtract x3 x2 + x + 3 from 3x3 2x2 7x + 6 and find the degree.

Solution

This can be written as ( 3x 3 2x2 7x + 6) ( x3 x 2 + x + 3)

When there is a –ve sign before the brackets, it can be removed by changing the sign of every term inside the bracket.

( 3x 3 2x2 7x + 6) ( x3 x 2 + x + 3) = 3x 3 2x2 7x + 6 x3 + x 2 x 3

= ( 3x 3x3 )+ (2x 2 + x2 )+ (7xx) + ( 63)

= x 3 ( 31) + x2 (2 + 1) + x (71) + ( 63)

= 2x 3x28x + 3

Hence, the degree of the expression is 3.

Example 3.17

Simplify and find the degree of the expression

( 4m2 + 3n) ( 3m + 9n2 ) ( 3m2 6n2 )+ ( 5m n)

Solution

( 4m2 + 3n) ( 3m + 9n2 ) ( 3m2 6n2 )+ ( 5m n)

= 4m2 + 3n 3m 9n2 3m2 + 6n2 + 5m n

= ( 4m2 3m2 )+ ( 3n n) + ( 3m + 5m) + ( 9n 2 + 6n2 )

= m2 + 2n + 2m 3n2

Hence, the degree of the expression is 2.

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