Degree of Expression
Let us recall about algebraic expression
which we have studied earlier.
1. Recap of Algebraic expression
We have learnt that while constructing
an algebraic expression, we use mathematical operators like addition, subtraction,
multiplication and division to combine variables and constants.
Now, we have learnt about exponents.
Note that exponential notations also can be used in the construction of Algebraic
expressions.
Let us recall some basic concepts about
expressions.
Consider the expression 2x +
3 , which is obtained by multiplying the variable x with the constant 2 and then adding the constant 3 to the product.
This expression is binomial as it contains two terms. The term 2x
is a variable term and 3 is a constant term. 2 is the co-efficient of x.
The terms with same variables are called
like terms. For example, –7x, 2x
and 5x are like terms. But, term with different variables are called unlike terms. For example, −2x , 7 y are unlike terms.
We can add or subtract like terms only.
We know that 2x + 5x =
7x . But, when we add unlike terms, it results in new expression. For example,
2x and 5y are unlike terms, thus resulting in new expression 2x
+
5y .
2. Degree of Expressions
To know the degree of an expression,
first let us try to understand the degree of a variable by relating it with the
exponents of numbers. Let us consider the square numbers. They have different base
and same exponents.
The geometrical representation of square
numbers are given below.
In general, if we consider the side of
a square as a variable ‘x’ then its area will be x × x sq. units.
This can be denoted as ‘x2’. Thus we have an algebraic expression
with exponent notation.
If we consider the term x2
as a monomial expression, the highest power of the expression is its exponent, that
is 2.
Similarly, when length ‘l ’ units and breadth ‘b’ units are variables of a rectangle, then
its area is l × b =
lb sq. units. We can consider lb
as a term in an algebraic expression, where l and b are factors of
lb.
The highest power of the expression lb is also 2, as we have to add up the powers of the variable factors.
Note
(i) When no exponent is
explicitly shown in a variable of a term, it is understood to be 1. For example,
11p = 11p1
.
(ii) For an expression in x, if the terms of the expressions
are in descending powers of x and the like terms are added, then we say that
it is in the standard form.
For example, x4
− 3x3 + 5x2 − 7x + 9 is in the standard form. It is easier to find the highest power
term when the expression is in standard form. Highest power of this expression is
4.
(iii) The highest degree
term of an algebraic expression is called as leading term.
Let us consider an algebraic expression:
x3 − 3x2 +
4 .
The terms of the above expression are
x3 , −3x2 and 4. Exponent
of the term x3 is 3 and −3x2 is 2.
Thus, the term x3 has
the highest exponent, that is 3.
Now, consider the expression, 3x4
−
4x3 y 2 + 8xy +
7 .
Take each term and check its power. In
3x4 , exponent is 4, hence its degree is 4. In − 4x
3 y2 , the sum of powers of x and y is
5, hence its degree is 5. In 8xy , the sum of powers is 2.
Therefore, the term with highest power
in the above expression is − 4x 3 y2
and its power is 5, which is called as degree
of this expression.
The term(s) containing the highest power
of the variables in an expression is called the degree
of expression.
The degree of any term in an expression
can only be a positive integer. Also, degree of expression doesn’t depend on the
number of terms, but on the power of variables in the individual terms. The degree
of constant term is 0.
Try these
1. Complete the following table:
2. Identify the like terms from the following:
(i) 2x2 y, 2xy2 , 3xy2
, 14x2 y, 7 yx
Like terms: 2x2y,
14x2y, 2xy2, 3xy2
(ii) 3x3 y2 , y 3x,
y3x2 , − y 3x,
3y 3x
Like terms: y3x,
– y3x, 3y3x
(iii) 11pq, − pq, 11pqr
, − 11pq , pq
Like terms: 11 pq, –pq, –11pq,
pq
Example 3.14
Find the degree of the following
expressions.
(i) x5
(ii) −3p3 q2
(iii) −4xy2 z3
(iv) 12xyz −
3x3 y2z +
z8
(v) 3a3b4
−
16c6 + 9b2c5
+
7
Solution
(i) In x5
, the exponent is 5. Thus, the degree of the expression is 5.
(ii) In −3p3q2
, the sum of powers of p and q is 5 (that is, 3+2). Thus, the degree
of the expression is 5.
(iii) In
−4xy2
z3 , the sum of powers of x, y and z is 6 (that
is, 1+2+3). Thus, the degree of the expression is 6.
(iv) The terms of the given expression
are 12xyz, 3x3 y2z, z8
Degree of each of the terms: 3, 6, 8
Terms with highest degree: z8
.
Therefore, degree of the expression is
8.
(v) The
terms of the given expression are 3a3b4 , −
16c6 , 9b2c5 , 7
Degree of
each of the terms: 7, 6, 7, 0
Terms with highest degree: 3a3b4
,9b2 c5
Therefore, degree of the expression is
7.
Example 3.15
Add the expressions 4x2 + 3xy + 9 y2 and 2x2 − 9xy + 6 y2 and find the degree.
Solution
This can be written as (4x2
+
3xy + 9 y2 ) + (2x2 −
9xy + 6 y2 )
Let us group the like terms, thus we
have
(
4x2 + 2x2 )+ ( 3xy −
9xy) + ( 9 y2 +
6 y2 ) = x2 (
4 +
2)
+
xy ( 3 − 9) +
y2 ( 9 + 6)
=6x2 − 6xy +
15y2
Thus, the degree of the expression is
2.
Example 3.16
Subtract x3 − x2 + x + 3 from 3x3 − 2x2 − 7x + 6 and find the degree.
Solution
This can be written as (
3x 3 − 2x2 −
7x + 6)−
(
x3 − x 2 +
x + 3)
When there is a –ve sign before the brackets,
it can be removed by changing the sign of every term inside the bracket.
(
3x 3 − 2x2 −
7x + 6)−
(
x3 − x 2 +
x + 3) = 3x 3 −
2x2 − 7x +
6 −
x3 + x 2 −
x – 3
= ( 3x 3 − x3 )+ ( −2x 2 + x2 )+ ( −7x − x) + ( 6 − 3)
= x 3 ( 3 − 1) + x2 ( −2 + 1) + x ( −7 − 1) + ( 6 − 3)
= 2x 3 − x2 − 8x + 3
Hence, the degree of the expression is
3.
Example 3.17
Simplify and find the degree
of the expression
(
4m2 + 3n)− ( 3m +
9n2 )−
(
3m2 − 6n2 )+ ( 5m −
n)
Solution
(
4m2 + 3n)− ( 3m +
9n2 )−
(
3m2 − 6n2 )+ ( 5m −
n)
= 4m2 +
3n − 3m − 9n2 −
3m2 + 6n2 +
5m – n
= ( 4m2 −
3m2 )+
(
3n − n) + ( −3m +
5m) + ( −9n 2 +
6n2 )
= m2 +
2n +
2m −
3n2
Hence, the degree of the expression is
2.
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