6th Maths : Term 3 Unit 1 : Fractions : Exercise 1.1 : Text Book Back Exercises Questions with Answers, Solution

**Exercise 1.1 **

** **

**1. Fill in the blanks **

i) 7 ¾ + 6 1/2 = __14 1/4__

ii) The sum of a whole number and a proper fraction
is called __mixed fraction__

iii) 5 1/3 − 3 1/2 = __1 5/6__

iv) 8 ÷ 1/2 = __16__

v) The number which has its own reciprocal is __1__

** **

**2. Say True or False**

i) 3 1/2 can be written as 3 + 1/2.**[True]**

ii) The sum of any two proper fractions
is always an improper fraction.**[ False]**

iii) The mixed fraction of 13/4 is
3 1/4.**[True]**

iv) The reciprocal of an improper fraction is always a proper fraction.**[True]**

v) 3 1/4 × 3 1/4 = 9 1/16**[ False]**

**3.
Answer the following:**

**i)
Find the sum of 1/7 and 3/9 .**

**ii)
What is the total of 3 1/3 and 4 1/6 ?**

**iii)
Simplify : 1 3/5 + 5 4/7.**

**iv)
Find the difference between 8/9 and 2/7 .**

**v)
Subtract 1 3/5 from 2 1/3 .**

**vi)
Simplify : 7 2/7 – 3 4/21**

**i) Find the sum of 1/7 and 3/9.**

1/7 + 3/9

[9 + 21] / [7 × 9] = 30/63 = 10/21

1/7 + 3/9 = 10/21

**ii) What is the total of 3 1/3 and 4 1/6 ?**

3 1/3 + 4 1/6

10/3 + 25/6

[20 + 25] / 6 = 45/6 = 7 (3/6)

= 7 1/2

= 3 1/3 + 4 1/6 = 7 1/2

**iii) Simplify: 1 3/5
+ 5 4/7**

8/5 + 39/7

[56+195] / [5 × 7] = 251/35
= 7 6/35

13/5 + 5 4/7 = 7 6/35

**iv) Find the difference between 8/9 and 2/7.**

8/9 – 2/7

[56 – 18] / [9 × 7] = 38/63

8/9 – 2/7 = 38/63

**v) Subtract 1 3/5 from 2
1/3**

2 1/3 − 1 3/5

7/3 − 8/5

[35 – 24] / [3 × 5] = 11/15

**vi) Simplify: 7 2/7 – 3 4/21.**

51/7 – 67/21

[153 – 67] / 21 = 86/21 = 4 (2/21)

7 (2/7) – 3 (4/21) = 4 (2/21)

** **

**4.
Convert mixed fractions into improper fractions and vice versa:**

**i)
3 7/18 ii) 99/7 iii) 47/6 iv) 12 1/9
**

** **

**5.
Multiply the following:**

**i)
2/3 ×** **6 ii) 8 1/3 ×5 iii) 3/8** **× 4/5 iv)
3 5/7** **×** **1 1/13 **

** **

**6.
Divide the following:**

** i) 3/7 ÷** **4 ii) 4/3 ÷ 5/9** ** iii) 4 1/5 ÷ 3 3/4 iv) 9 2/3 ÷ 1 2/3 **

** **

**7. Gowri purchased 3 1/2 kg of tomatoes, 3/4 kg of
brinjal and 1 1/4 kg of onion. What is
the total weight of the vegetables she bought? **

Weight of tomatoes = 3 ½ *kg*

Weight of brinjal = ¾ *kg*

Weight of Onion = 1 ¼ *kg*.

Total weight of vegetables Gowri bought

= (3 ½ + ¾ + 1 ¼ ) *kg*

= ( 7/2 + 3/4 + 1 1/4 ) *kg*

= ( [14 + 3 + 5] / 4 ) *kg* 22/4 *kg* = 5 2/4 *kg*

= 5 1/2 *kg*

**Total weight of vegetables Gowri bought = 5 ½ kg.**

** **

**8.
An oil tin contains 3 3/4 litres of oil of which 2 ½ litres of oil is used. How much oil is left over?
**

Capacity of oil in the oil tin = 3 ¾ litres

Capacity of oil used = 2 ½ litres

Capacity of oil left over = (3 ¾ − 2 ½ ) litres

= 15/4 – 5/2 = [15 – 10] / 4 =
5/4 litre

= 1 ¼ litre

**Capacity of oil leftover = 1 ¼ litre**

** **

** 9. Nilavan can walk 4 1/2 km in an hour. How much distance will he cover in 3 1/2 hours? **

Distance covered by Nilavan in an hour = 4 ½ km

Distance covered in 3 ½
hours = 4 ½ × 3 ½ km

= 9/2 × 7/2 = 63/4 = 15 3/4 km

**Distance covered in 3 ½
hours = 15 ¾ km **

** **

**10**.** ****Ravi bought a curtain
of length 15 3/4 m. If he cut the curtain into small pieces each of length 2
1/4 m, then how many small curtains will he get? **

Total length of curtain = 15 3/4 *m*

Length of smal curtain
cut off = 2 1/4 m

Number of small.curtains he will get = Total length / Length of
1 small curtain

= 15 ¾ / 2 ¼

= 15 ¾ ÷ 2 ¼

= 63/4 ÷ 9/4

= (63/4) × (4/9) = 7

**Number of small.curtains he will get = 7.**

__Objective
Type Questions__

**11.
Which of the following statement is incorrect? **

a) 1/2 >
1/3

b) 7/8 > 6/7

c) 8/9 < 9/10

d) 10/11< 9/10

*Answer:***d) 10/11 > 9/10**

**12.
The difference between 3/7 and 2/9 is **

a) 13/63

b) 1 /9

c) 1/7

d) 9/16

*Answer: *a) 13/63

**13.
The reciprocal of 53/17 is **

a) 53/17

b) 5 3/17

c) 17/53

d) 3 5/17

*Answer: *c) 17 / 53

**14.
If 6/7 = Α/49, then the value of A is **

a) 42

b) 36

c) 25

d) 48

*Answer:***a) 42**

**15.
Pugazh has been given four choices for his pocket money by his father. Which of
the choices should he take in order to get the maximum money?**

a) 2/3 of ₹150

b) 3/5 of
₹150

c) 1/5 of
₹150

d) 1/5 of
₹150

*Answer :***c) 1/5 of ₹ 150**

__ANSWERS:__

__Exercise 1.1 __

**1. i) 14 1/4 ii) Mixed Fraction iii) 1 5/6 iv) 16 v) 1 **

**2. i) True ii) False
iii) True iv) True v) False **

**3. i) 10/21 ii) 7
½ iii) 7 6/35 iv) 38/63
v) 11/15 vi) 4 2/21**

**4. i) 61/18 ii) 14
1/7 iii) 7 5/6 iv) 109 /9**

**5. i) 4 ii) 41
2/3 iii) 3/10 iv) 4 **

** 6. i) 3/28
ii) 2 2/5 iii) 1 3/25 iv) 5 4/5 **

**7. 5 1/2 kg **

**8. 1 1/4 l **

**9. 15 3/4 km **

**10. 7 **

**11. d) 10/11 < 9/10**

**12. a) 13/63**

**13 c) 17/53 **

**14. a) 42 **

**15. c) 4/5 of ₹150**

** **

Tags : Questions with Answers, Solution | Fractions | Term 3 Chapter 1 | 6th Maths , 6th Maths : Term 3 Unit 1 : Fractions

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6th Maths : Term 3 Unit 1 : Fractions : Exercise 1.1 | Questions with Answers, Solution | Fractions | Term 3 Chapter 1 | 6th Maths

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