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# Exercise 2.1 (Area and Perimeter of the Parallelogram)

7th Maths : Term 1 Unit 2 : Measurements : Exercise 2.1 : Text Book Back Exercises Questions with Answers, Solution

Exercise 2.1

1. Find the area and perimeter of the following parallelograms: Given base b = 11 cm

Height h = 3 cm

Area of the Parallelogram = b × h sq.units

= 11 × 3 = 33 sq.cm

Perimeter of the Parallelogram = Sum of the length of the four sides

= (11+ 4+11+ 4) cm

= 30 cm Given base b = 7 cm

Height h = 10 cm

Area of the Parallelogram = b × h sq.units

= 7 × 10 = 70 sq.cm

Perimeter of the Parallelogram = Sum of the length of the four sides

= (13 + 7+ 13 + 7) cm

= 40 cm

2. Find the missing values.  3. Suresh won a parallelogram-shaped  trophy in a state level Chess tournament. He knows that the area of the trophy is 735 sq. cm and its base is 21 cm. What is the height of that trophy? Area of the parallelogram Trophy = 735 sq.cm

base b = 21 cm

We know that,

Area of the parallelogram = b × h = 735 sq.cm

21 × h = 735

h = 735 / 21= 35 cm

The height of that trophy = 35 cm

4. Janaki has a piece of fabric in the shape of a parallelogram. Its height is 12 m and its base is 18 m. She cuts the fabric into four equal parallelograms by cutting the parallel sides through its mid-points. Find the area of each new parallelogram.

Height of the parallelogram h = 12 m

base b = 18 m

Area of the parallelogram = b ×  h sq.inits

= 18 × 12 sq.m

= 216 sq. m

Area of 4 parallelogram = 216 sq. m

Area of 1 parallelogram = 216 ÷ 4 sq. m = 54 sq. m

Area of each new parallelogram = 54 sq.m

5. A ground is in the shape of parallelogram. The height of the parallelogram is 14 metres and the corresponding base is 8 metres longer than its height. Find the cost of eveling the ground at the rate of 15 per sq. m.

Height of the parallelogram h = 14 m

base b = 8m longer than its height

= (8+ 14) m = 22 m

Area of the parallelogram = b  × h sq. units

= 22 × 14 sq. m

= 308 sq. m

Cost of levelling 1 sq.m = ₹ 15

Cost of levelling 308 sq.m = ₹ 308 × 15

= ₹ 4620

Cost of levelling the ground = ₹ 4620

Objective type questions

6. The perimeter of a parallelogram whose adjacent sides are 6 cm and 5 cm is

(i) 12 cm

(ii) 10 cm

(iii) 24 cm

(iv) 22 cm

7. The area of a parallelogram whose base 10 m and height 7 m is

(i) 70 sq. m

(ii) 35 sq. m

(iii) 7 sq. m

(iv) 10 sq. m

8. The base of the parallelogram with area is 52 sq. cm and height 4 cm is

(i) 48 cm

(ii) 104 cm

(iii) 13 cm

(iv) 26 cm

9. What happens to the area of the parallelogram, if the base is increased 2 times and the height is halved?

(i) Decreases to half

(ii) Remains the same

(iii) Increases by two times

(iv) none

10. In a parallelogram the base is three times its height. If the height is 8 cm then the area is

(i) 64 sq. cm

(ii) 192 sq. cm

(iii) 32 sq. cm

(iv) 72 sq. cm

Exercise 2.1

1. (i) area = 33 sq.cm perimeter = 30cm (ii) area = 70 sq.cm perimeter = 40 cm

2. (i) 90 sq.cm (ii) 7 m (iii) 13 mm

3. 35 cm

4. 54 sq.cm

5. ₹ 4620/-

Objective type questions

6. (iv) 22 cm

7. (i) 70 sq.m

8. (iii) 13 cm

9. (ii) Remains the same

10. (ii) 192 sq.cm

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7th Maths : Term 1 Unit 2 : Measurements : Exercise 2.1 (Area and Perimeter of the Parallelogram) | Questions with Answers, Solution | Measurements | Term 1 Chapter 2 | 7th Maths