7th Maths : Term 1 Unit 2 : Measurements : Exercise 2.1 : Text Book Back Exercises Questions with Answers, Solution

**Exercise 2.1**

**1. Find the area and
perimeter of the following parallelograms:**

Given base *b* = 11 *cm*

Height *h* = 3 *cm*

Area of the Parallelogram =*
b × h sq.units*

= 11 × 3 = 33 *sq.cm*

Perimeter of the Parallelogram = Sum of the length of the four
sides

= (11+ 4+11+ 4) *cm*

** = 30 cm**

Given base *b* = 7 *cm*

Height* h* = 10* cm*

Area of the Parallelogram = *b
× h sq.units*

= 7 *×*
10 = 70 *sq.cm*

Perimeter of the Parallelogram = Sum of the length of the four
sides

= (13 + 7+ 13 + 7) *cm*

** = 40 cm**

** **

**2.
Find the missing values.**

**Answer: **

** **

**3.
Suresh won a parallelogram-shaped trophy
in a state level Chess tournament. He knows that the area of the trophy is 735 ***sq.
cm*** and its base is 21 ***cm***. What is the
height of that trophy?**

**Answer: **

Area of the parallelogram Trophy = 735 *sq.cm*

base *b* = 21 *cm*

We know that,

Area of the parallelogram = *b
× h* = 735 *sq.cm*

21 × *h* = 735

* h* = 735 / 21= 35 cm

**The height of that
trophy = 35 cm**

** **

**4. Janaki has a piece of fabric in the shape of
a parallelogram. Its height is 12 ***m*** and its base is 18 ***m.*** She cuts the
fabric into four equal parallelograms by cutting the parallel sides through its
mid-points. Find the area of each new parallelogram.**

Height of the parallelogram *h*
= 12 *m*

base *b*
= 18 *m*

Area of the parallelogram = *b*
× * h sq.inits*

= 18 × 12 *sq.m*

= 216 *sq.
m*

Area of 4 parallelogram = 216 *sq. m*

Area of 1 parallelogram = 216 ÷ 4 *sq. m* = 54 *sq. m*

**Area of each new
parallelogram = 54 sq.m**

** **

**5.
A ground is in the shape of parallelogram. The height of the parallelogram is
14 metres and the corresponding base is 8 metres longer than its height. Find
the cost of eveling the ground at the rate of ****₹**** 15 per ***sq. m***.**

Height of the parallelogram *h*
= 14 *m*

base *b*
= 8*m* longer than its height

= (8+ 14) *m*
= 22 *m*

Area of the parallelogram = *b
* × *h sq. units*

= 22 × 14 *sq.
m*

= 308 *sq.
m*

Cost of levelling 1 sq.m = ₹ 15

Cost of levelling 308
sq.m = ₹ 308 × 15

= ₹ 4620

**Cost of levelling
the ground = ₹ 4620**

** **

__Objective
type questions__

**6. The perimeter of a parallelogram whose
adjacent sides are 6 ***cm*** and 5 ***cm*** is**

(i)
12 *cm*

(ii)
10 *cm*

(iii)
24 *cm*

(iv)
22 *cm*

**Answer: (iv) 22 cm**

**7. The area of a parallelogram whose base 10 ***m*** and height 7 ***m*** is**

(i)
70 *sq. m*

(ii)
35 *sq. m*

(iii)
7 *sq. m*

(iv)
10 *sq. m*

**Answer: (i) 70 sq.
m**

**8. The base of the parallelogram with area is
52 ***sq. cm*** and height 4 ***cm*** is**

(i)
48 *cm*

(ii)
104 *cm*

(iii)
13 *cm*

(iv)
26 *cm*

**Answer: (iii) 13 cm**

**9.
What happens to the area of the parallelogram, if the base is increased 2 times
and the height is halved?**

(i) Decreases to half

(ii) Remains the same

(iii) Increases by two times

(iv) none

**Answer: (ii) Remains the same**

**10.
In a parallelogram the base is three times its height. If the height is 8 ***cm*** then the area
is**

(i) 64 *sq.
cm*

(ii) 192 *sq.
cm*

(iii) 32 *sq.
cm*

(iv) 72 *sq.
cm*

**Answer: (ii) 192 sq.
cm**

** **

**ANSWERS**

**Exercise 2.1 **

1. (i) area = 33* sq.cm *perimeter = 30*cm* (ii) area = 70* sq.cm *perimeter = 40 *cm*

2. (i) 90* sq.cm *(ii) 7* m *(iii) 13* mm*

3. 35* cm *

4. 54* sq.cm *

5. ₹ 4620/-

**Objective type questions **

6. (iv) 22* cm *

7. (i) 70* sq.m *

8. (iii) 13* cm *

9. (ii) Remains the same

10. (ii) 192* sq.cm*

* *

Tags : Questions with Answers, Solution | Measurements | Term 1 Chapter 2 | 7th Maths , 7th Maths : Term 1 Unit 2 : Measurements

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7th Maths : Term 1 Unit 2 : Measurements : Exercise 2.1 (Area and Perimeter of the Parallelogram) | Questions with Answers, Solution | Measurements | Term 1 Chapter 2 | 7th Maths

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