7th Maths : Term 3 Unit 1 : Number System : Miscellaneous Practice problems, Challenge Problems, Text Book Back Exercises Questions with Answers, Solution

**Exercise
1.5**

** **

__Miscellaneous
Practice problems__

** **

**1. Malini bought three ribbons of length
13.92 m, 11.5 m and 10.64 m. Find the total length of the ribbons?**

**Solution: **

Length of ribbon 1 = 13.92 m

Length of ribbon 2 = 11.50 m

Length of ribbon 3 = 10.64 m

Total Length of the ribbons = 13.92 m + 11.5 m + 10.64 m = 36.06
m

Total length of the ribbons= 36.06m

** **

**2. Chitra has bought 10 kg 35
g of ghee for preparing sweets. She used 8 kg 59 g of ghee.
How much ghee will be left?**

**Solution: **Total weight of
ghee bought = 10 kg 35 g

Weight of ghee used = 8 kg 59 g

Weight of ghee left = 10.35 kg – 8.59 kg = 1.76 kg

∴ Weight of ghee left = 1 kg 76 g = 1.76 kg

** **

**3. If the capacity of a milk can is 2.53
l, then how much milk is required to fill 8 such cans?**

**Solution:**

Capacity of 1 milk can = 2.53 *l*

∴ Capacity of 8 milk cans = 2.53 *l* × 8 = 20.24 *l*

To fill 8 cans 20.24 *l*
of milk is required.

** **

**4. A basket of orange weighs 22.5 kg.
If each family requires 2.5 kg of orange, how many families can share?**

**Solution:**

Total weight of orange = 22.5 kg

Weight of orange required for 1 family = 2.5 kg

∴ Number of families sharing orange = 22.5.kg ÷ 2.5 kg

:. 9 families can share the oranges = 22.5 / 2.5 = 22.5/2.5 × 10/10
= 225 / 25 = 9

** **

**5. A baker uses 3.924 kg of sugar
to bake 10 cakes of equal size. How much sugar is used in each cake?**

**Solution:**

** **For 10 cakes sugar
required = 3.924 kg

For 1 cake sugar required = 3.924 ÷ 10 = 3.924 / 10 = 0.3924 kg

For 1 cake sugar required = 0.3924 kg.

** **

**6. Evaluate: (i) 26.13 ****×**** 4.6
(ii) 3.628 ****+**** 31.73 ****−****2.1**

**Solution: **

(i) 26.13 × 4.6

26.13 × 4.6 = 120.198

(ii) 3.628 + 31.73 – 2.1 = 33.258

** **

**7. Murugan bought some bags of vegetables.
Each bag weighs 20.55 kg. If the total weight of all the bags is 308.25 kg,
how many bags did he buy?**

**Solution: **

Total weight of all bags = 308.25 kg

Weight of 1 bag = 20.55 kg

∴ Number of bags = Total weight / Weight of 1 bag

= 308.25 / 20.55 = (
30825 /100 ) / (2055 / 100 )

= (30825 /1000) × 100 /
2055

= 30825 / 2055 = 2055 /
137 = 15

∴ He bought 15 bags.

** **

**8. A man walks around a circular park
of distance 23.761 m. How much distance will he cover in 100 rounds?**

**Solution: ** In 1 round distance
covered = 23.761 m

∴ In 100 rounds distance = 23.761 × 100

=
2376.1 m

∴ In 100 round he covers 2376.1 m.

** **

**9. How much 0.0543 is greater than 0.002?**

**Solution:**

Greater number =
0.0543 (–)

Smaller number = __0.0020__

= __0.0523__

∴ Required answer is 0.0523

** **

**10.
A printer can print 15 pages per minute. How many pages can it print in 4.6 minutes?**

**Solution:**

In 1 minute the pages printed = 15

In 4.6 minutes the pages printed = 15 × 4.6

= 69

The printer prints 69 pages. 460

** **

__Challenge
Problems__

** **

**11. The distance travelled by Prabhu
from home to Yoga centre is 102 m and from Yoga centre to school is 165 m.
What is the total distance travelled by him in kilometres (in decimal form)?**

**Solution: **

Distance from home to yoga centre = 102 m (+)

Distance from yoga centre to school = __165 m__

Total distance = __267 m__

1000 meters = 1 km

∴ 267 metres = 267 / 1000 km = 0.267 km

∴ Total distance travelled = 0.267 km

** **

**12. Anbu and Mala travelled from A to
C in two different routes. Anbu travelled from place A to place B and from there
to place C. A is 8.3 km from B and B is 15.6 km from C. Mala travelled
from place A to place D and from there to place C. D is 7.5 km from A and
C is 16.9 km from D. Who travelled more and by how much distance?**

**Solution:**

**Distance travelled
by Anbu:**

From place A to place B = 8.3 km

Distance from place B to place C = 15.6 km

∴ Total distance travelled by Anbu = 8.3 + 15.6

= 23.9 km

**Distance travlled
by Mala:**

Distance travelled place A to D = 7.5 km

Distance from place D to place C = 16.9 km

Total distance travelled by mala = (7.5 + 16.9) km = 24.4 km

24.4 > 23.9

∴ Mala travelled more distance. She travelled (24.4 – 23.9) km
more

i.e she travelled 0.5 km
more.

** **

**13.
Ramesh paid ₹ 97.75 per hour for a taxi and he used 35 hours in a week. How much
he has to pay totally as taxi fare for a week?**

**Solution:**

Payment for the taxi for an hour = ₹ 97.75

Total hours the taxi was used = 35 hrs.

∴ Total payment for the taxi for the week

= 97.75 × 35

= 3421.25

Total payment for a week = ₹ 3421.25

** **

**14. An Aeroplane travelled 2781.20 kms
in 6 hours. Find the average speed of the aeroplane in km/hr.**

**Solution:**

In 6 hours the distance travelled = 2781.20 km

In 1 hour the distance travelled = 2781.20 / 6 km

= (278120/ 100 ) / ( 6 /
1)

= (278120/100) × 1/6

= [278120 / 6] × [1 / 100]
= 46353 × 1 / 100

= 463.53 km

Average speed of the aroplane = 463.53 km/hr.

** **

**15.
Kumar’s car gives 12.6 km mileage per litre. If his fuel tank holds 25.8
litres then how far can he travel?**

**Solution:**

Distance travelled with 1 litre fuel = 12.6 km

∴ with 25.8 litres distance travelled = 12.6 × 25.8

= 325.08 km

The car can travel 325.08 km

** **

__ANSWERS:__

**Exercise 1.5 **

1. 36.06* m *

2. 1.976* kg *

3. 20.242

4. 9

5. 0.3924 *kg*

6.(i)120.198 (ii)
33.258

7. 15

8. 2376.1* m *

9. 0.0523

10. 69 pages

** Challange Problems **

11. 0.267* km *

12. Mala travelled 0.5* km *more than Anbu.

13. ₹ 3421.25

14. 463.53 *km/hour *

15. 325.08* km*

* *

Tags : Questions with Answers, Solution | Number System | Term 3 Chapter 1 | 7th Maths , 7th Maths : Term 3 Unit 1 : Number System

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7th Maths : Term 3 Unit 1 : Number System : Exercise 1.5 | Questions with Answers, Solution | Number System | Term 3 Chapter 1 | 7th Maths

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