Estimation of
Ferrous Ammonium Sulphate (FAS)
To
estimate the amount of ferrous ammonium sulphate (FAS) dissolved in 1500 ml of
the given unknown solution volumetrically. For this you are given with a
standard solution of ferrous sulphate ( FeSO4 )of normality 0.1024 N
and potassium permanganate solution as link solution.
Oxidation : 5 Fe2+ → 5 Fe3+ + 5e−
Reduction: 5Fe2+ + MnO4−
+ 8H+ → 5Fe3+ + Mn2+ + 4H2O
Overall reaction: 5Fe2+ + MnO4−
+ 8H+ → 5Fe3+ + Mn2+ + 4H2O
Short procedure:
(Link
KMnO4)Vs (Standard FeSO4
)
Burette
is washed with water, rinsed with KMnO4 solution and filled with
same solution up to the zero mark. Exactly 20 ml of standard FeSO4
solution is pipetted out into the clean, washed conical flask. To this
solution, approximately 20ml of 2N sulphuric acid is added. This mixture is
titrated against KMnO4 Link solution from the burette. KMnO4
is added drop wise till the appearance of permanent pale pink colour. Burette
reading are noted, the same procedure is repeated to get concordant values.
(Link
KMnO4)Vs (Standard FeSO4
)
Volume of
KMnO4 (link) solution V1
= ml
Normality
KMnO4 (link) solution N1 = ?N
Volume of
standard FeSO4 solution V2 = 20
ml
Normality
of standard FeSO4 solution N2 = 0.1024
N
According
to normality equation: V1× N1 = V2 × N2
N1
= V2 × N2 / V1
Normality
of KMnO4 (link) solution (N1) = ----------X--------- N
(Unknown FAS) Vs (Link KMnO4 )
Burette
is washed with water, rinsed with KMnO4 solution and filled with
same KMnO4 solution up to the zero mark. Exactly 20 ml of unknown
FAS solution is pipetted out into the clean, washed conical flask. To this FAS
solution approximately 20ml of 2N sulphuric acid is added. This mixture is
titrated against KMnO4 Link solution from the burette. KMnO4
is added drop wise till the appearance of permanent pale pink colour. Burette
reading is noted and the same procedure is repeated to get concordant values.
(Link
KMnO4)Vs (Unknown FAS)
Volume of
Unknown FAS solution V1 =
20ml
Normality
of Unknown FAS solution N1 = N
Volume of
KMnO4 (link) solution V2 = ml
Normality
KMnO4 (link) solution
According
to normality equation: V1× N1 = V2 ×
N2
N1 = V2 × N2 / V1
N1=
------------------------ N
The
normality of unknown FAS solution =
--------Y---N
The
amount of FAS dissolved in 1 lit of the solution = (Normality) x (equivalent
weight)
The amount
of FAS dissolved in 1500 ml of the solution = Normality × equivalentweight × 1500 / 1000
= Y × 392 × 1500 /
1000
= g
The
amount of FAS dissolved in 1500 ml of the solution = g
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