1.A metal bar of 10mm dia when subjected to a pull of 23.55KN gave and elongation of 0.3mm on a gauge length of 200mm. In a torsion test maximum shear stress of 40.71N/mm2 was measured on a bar of 50mm dia. The angle of twist measured over a length of 300mm being 0°21’. Deter poisson’s.
diad = 10mm
pull P = 23.55KN
elongation SL = 0.3mm
Gauge length = 200mm
(or) = 40.71 N/mm2
Dia = 500mm
Twist angle = 0o21’
length = 300 mm
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What must be the length of a 5mm dia aluminium wine so that it can be twisted through 1 complete revolution without exceeding a shear of 42N/mm2. Take, G=27 GPO.
A solid steel shaft has to transmit 75Kw power at 200 pm. Taking allowable shear stress 70Mpo. Find suitable dia of shaft with the maximum torque transmitted on each revolutions exceeds by mean by 30% 1.3 times mean.