Science : Optics: Solved Problems, Solved Example Problems with Answers, Solution

**Optics ****Science**

SOLVED PROBLEMS

Light rays travel from vacuum into a glass whose refractive index is 1.5. If the angle of incidence is 30Â°, calculate the angle of refraction inside the glass.

accorting to Snellâ€™s law,

sin i / sin r = Âµ2/ Âµ1

Âµ1 sin i = Âµ2 sin r

Here Âµ1 = 1.0,

Âµ2 = 1.5, i = 30Â°

(1.0) sin 30Â° = 1.5 sin r

1Ã— 1/2 = 1.5 sin r

sin r = 1/(2Ã—1.5) = 1/3 = (0.333)

r= sinâ€“1 (0.333)

r = 19.45Â°

A beam of light passing through a diverging lens of focal length 0.3m appear to be focused at a distance 0.2m behind the lens. Find the position of the object.

f = âˆ’0.3 m, v = âˆ’0.2 m

A person with myopia can see objects placed at a distance of 4m. If he wants to see objects at a distance of 20m, what should be the focal length and power of the concave lens he must wear?

Given that x = 4m and y = 20m.

Focal length of the correction lens is

f = â€‰â€‰â€‰xy / â€‰xâˆ’yâ€‰ (Refer eqn.2.7)

Power of the correction lens

For a person with hypermeteropia, the near point has moved to 1.5m. Calculate the focal length of the correction lens in order to make his eyes normal.

Given that, d = 1.5m; D = 25cm = 0.25m (For a normal eye).

From equation (2.8), the focal length of the correction lens is

f = â€‰d Ã— D / â€‰d âˆ’ D = â€‰1.5 Ã— 0.25 / 1.5 âˆ’ 0.25 = â€‰0.375 /â€‰1.25 = 0.3 m

Tags : Science , 10th Science : Chapter 2 : Optics

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10th Science : Chapter 2 : Optics : Solved Problems: Optics | Science

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