Numerical Problems

Numerical Problems

Solved examples

1. How much will the temperature of 68°F be in Celsius and Kelvin?

Given :

Temperature in Fahrenheit   =F=68°F

Temperature in Celsius        =C=?

Temperature in Kelvin        =K=?

(F-32) /9 = C/5

(68-32) / 9 = C/5

C = 5 × 36/9 = 20°C

K = C + 273.15 = 20 + 273.15 = 293.15

Thus, the temperature in Celsius = 20ºC and in Kelvin = 293.15 K

2. At what temperature will its value be same in Celsius and in Fahrenheit?

Given : If the temperature in Celsius is C, then the temperature in Fahrenheit (F) will be same,

i.e. F = C.

(F-32)/9= C/5

(or)

(C-32) / 9 = C / 5

(C-32) × 5 = C x 9

5C 160       = 9C

4 C       = 160

C = F  = 40

The temperatures in Celsius and in Fahrenheit will be same at – 40

3. Convert the given temperature :

1. 45°C = 113 °F

2. 20°C = 68 °F

3. 68°F = 292.15 K = 20 °F

4) 185°F = 85 °C

5.  0°C = 273.15 K

6.  -20°C = 253.15 K

7. 100K = -173.15 °C

8) 272.15 K = -1 °C