Heat and Temperature : Solved examples , Numerical Problems

**Numerical
Problems**

** **

**Solved examples**

**1. How much will the temperature of 68****°****F be in Celsius and Kelvin?**

**Given :**

Temperature
in Fahrenheit =F=68°F

Temperature
in Celsius =C=?

Temperature
in Kelvin =K=?

(F-32) /9
= C/5

(68-32) /
9 = C/5

C = 5 ×
36/9 = 20°C

K = C +
273.15 = 20 + 273.15 = 293.15

Thus, the
temperature in Celsius = 20ºC and in Kelvin = 293.15 K

**2. At what temperature will its value be same in
Celsius and in Fahrenheit?**

**Given : **If the
temperature in Celsius is C, then** **the temperature in Fahrenheit (F) will
be same,

i.e. F =
C.

(F-32)/9=
C/5

(or)

(C-32) / 9
= C / 5

(C-32) ×
5 = C x 9

5C 160 = 9C

4 C = 160

C = F = 40

The temperatures
in Celsius and in Fahrenheit will be same at – 40

**3. Convert the given temperature : **

1. 45°C =
__113__ °F

2. 20°C =
__68__ °F

3. 68°F =
__292.15__ K = __20__ °F

4) 185°F =
__85__ °C

5. 0°C = __273.15__
K

6. -20°C = __253.15__
K

7. 100K =
__-173.15__ °C

8) 272.15
K = __-1__ °C

Tags : Solved examples | Heat and Temperature | Term 2 Unit 1 | 7th Science , 7th Science : Term 2 Unit 1 : Heat and Temperature

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