6th Maths : Term 1 Unit 3 : Ratio and Proportion : Text Book Back Exercises Questions with Answers, Solution

__Exercise
3.1__

** **

**1. Fill in the blanks.**

**(i) Ratio of ₹ 3 to ₹ 5 = **__3 : 5__**.**

**(ii) Ratio of 3m to 200 cm = **

**(iii) Ratio of 5 km 400 m to 6 km = **

**(iv) Ratio of 75 paise to ₹ 2 = **__3 : 8. [75 : 200]__**.**

** **

**2. Say whether the following statements
are True or False.**

**(i) The ratio of 130 cm to 1 m is 13 : 10.**

**(ii) One of the terms in a ratio cannot
be 1.**

** **

**3. Find the simplified form of the
following ratios.**

**(i) 15 : 20 (ii) 32 : 24 (iii) 7 :
15 (iv) 12 : 27 (v) 75 : 100**

**Solution: **

**(i) 15 : 20**

Fractional form = (15 ÷ 5) / (20 ÷ 5) = 3 / 4

Simplest form = 3 : 4

**(ii) 32 : 24**

Fractional form = [32 ÷ 8] / [24
÷ 8] = 4 / 3

Simplest form = 4 : 3

**(iii) 7 : 15**

Fractional form = 7 / 15 (No common divisor)

Simplest form = 7 : 15

**(iv) 12 : 27**

Fractional form = [12 ÷ 3] / [27 ÷
3] = 4 / 9

Simplest form = 4 : 9

**(v) 75: 100**

Fractional form = [75 ÷ 25] / [100 ÷ 25] = 3 / 4

Simplest form = 3 : 4

** **

**4. Akilan walks 10 km in an hour while Selvi walks 6 km in an hour. Find the simplest ratio of
the distance covered by Akilan to that of Selvi.**

**Solution:**

Akilan walks in an hour = 10 km

Selvi walks in an hour = 6 km

Ratio of distance covered by both = 10 : 6

Simplest form:

[10 ÷ 2] / [6 ÷
2] = 5 / 3

Distance covered by Akilan and Selvi = 5 : 3

** **

**5. The cost of parking a bicycle is
₹ 5 and the cost of parking a scooter is ₹ 15. Find the simplest ratio of the parking
cost of a bicycle to that of a scooter.**

**Solution:**

Parking cost of a bicycle = Rs. 5

Parking cost of a scooter = Rs.15

Simplest ratio of bicycle to scooter

[5 ÷ 5] / [15 ÷
5] = 1 / 3

Ratio of bicycle to scooter = 1 : 3

** **

**6. Out of 50 students in a class,
30 are boys. Find the ratio of**

**(i) number of boys to the number of
girls.**

**(ii) number of girls to the total
number of students.**

**(iii) number of boys to the total
number of students.**

**Solution:**

Total No. of students = 50

No. of boys = 30

No. of girls = 50 − 30

= 20 girls

(i) number of boys to the number of girls.

boys : girls = 30 : 20

Simplest form = [30 ÷ 10] / [20
÷ 10] = 3 / 2

boys : girls = 3:2

(ii) number of girls to the total number of students.

girls : total students = 20 : 50

Simplest form = [20 ÷ 10] / [50 ÷ 10] = 2 / 5

girls : students = 2 : 5

(iii) number of boys to the total number of students.

boys : total students = 30 : 50

Simplest form = [30 ÷ 10] / [50
÷ 10] = 3 / 5

boys : students = 3 : 5

** **

__Objective
Type Questions__

** **

**7. The ratio of ₹ 1 to 20 paise is
__________.**

**(a) 1 : 5 **

**(b) 1 : 2 **

**(c) 2 : 1 **

**(d) 5 : 1**

**Answer:** (d) 5 : 1

** **

**8. The ratio of 1 m to 50 cm is __________.**

**(a) 1 : 50 **

**(b) 50 : 1 **

**(c) 2 : 1**

**(d) 1 : 2**

**Answer:** (c) 2 : 1

** **

**9. The length and breadth of a window
are in 1m and 70 cm respectively. The
ratio of the length to the breadth is ____________.**

**(a) 1 : 7 **

**(b) 7 : 1 **

**(c) 7 : 10 **

**(d) 10 : 7**

**Answer:** (d) 10:7

** **

**10. The ratio of the number of sides
of a triangle to the number of sides of a rectangle is**

**(a) 4 : 3 **

**(b) 3 : 4 **

**(c) 3 : 5 **

**(d) 3 : 2**

**Answer:** (b) 3 : 4

** **

**11. If Azhagan is 50 years old and
his son is 10 years old then the simplest ratio between the age of Azhagan to his
son is**

**(a) 10 : 50 **

**(b) 50 : 10**

**(c) 5 : 1 **

**(d) 1 : 5**

**Answer:** (c) 5 : 1

** **

__Answers:__

__Exercise 3.1__

**1) (i) 3 : 5 (ii) 3 : 2 (iii) 9 : 10 (iv) 3 : 8 **

**2) (i) True (ii) False **

**3) (i) 3 : 4 (ii) 4 : 3 (iii) 7 : 15 (iv) 4 : 9 (v) 3 : 4**

**4) 5 : 3**

**5) 1 : 3**

**6) (i) 3 : 2 (ii) 2 : 5 (iii) 3 : 5**

**7) (d) 5 : 1**

**8) (c) 2 : 1**

**9) (d) 10 : 7**

**10. (b) 3 : 4**

**11. (c) 5 : 1**

Tags : Questions with Answers, Solution | Ratio | Term 1 Chapter 3 | 6th Maths , 6th Maths : Term 1 Unit 3 : Ratio and Proportion

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6th Maths : Term 1 Unit 3 : Ratio and Proportion : Exercise 3.1 | Questions with Answers, Solution | Ratio | Term 1 Chapter 3 | 6th Maths

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