Division of Polynomials
Let us consider the numbers 13 and 5. When 13 is
divided by 5 what is the quotient and remainder.?
Yes, of course, the quotient is 2 and the remainder
is3.We write 13 = (5×2)+3
Let us try.
From the above examples, we observe that the
remainder is less than the divisor.
Can we say ? that when the remainder is 0, then the
dividend is the multiple of the divisor?
Dividend = ( Divisor × Quotient ) + Remainder.
Is it possible to divide one polynomial by another
?
Of course, yes, and the way to do it is just the
way similar to what you do with numbers!
Let us start with the division of a polynomial by a
monomial.
Divide x3 -4x2 + 6x by x, where , x ≠ 0
Solution
We have
Let p(x) and g(x) be two polynomials such that
degree of p(x) ≥degree of
g(x) and g(x) ≠ 0. Then
there exists unique polynomials q(x) and r(x) such that
p(x) = g (x) x q(x) + r(x) … (1)
where r(x) = 0 or degree of r(x) < degree of
g(x).
The polynomial p(x) is the Dividend, g(x) is the
Divisor, q(x) is the Quotient and r(x) is
the Remainder. Now (1) can be written as
Dividend = (
Divisor × Quotient ) + Remainder.
If r(x) is zero, then we say p(x) is
a multiple of g(x). In other words, g(x)
divides p(x).
If it looks complicated, don’t worry ! it is
important to know how to divide polynomials, and that comes easily with
practice. The examples below will help you.
Find the quotient and the remainder
when (5x2-7x+2) / (x-1)
Solution
Find quotient and the remainder when f(x) is divided by g(x)
(i) f(x) = (8x3–6x2+15x–7),
g(x) = 2x+1. (ii) f(x)
= x3 + 1, g(x) = x+1
Solution
If x4 –3x3
+ 5x2 –7 is divided by x2 + x + 1 then find the quotient and the remainder.
Solution
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