1.A metal bar of 10mm dia when subjected to a pull of 23.55KN gave and elongation of 0.3mm on a gauge length of 200mm. In a torsion test maximum shear stress of 40.71N/mm2 was measured on a bar of 50mm dia. The angle of twist measured over a length of 300mm being 0°21’. Deter poisson’s.
diad = 10mm
pull P = 23.55KN
elongation SL = 0.3mm
Gauge length = 200mm
(or) = 40.71 N/mm2
Dia = 500mm
Twist angle = 0o21’
length = 300 mm
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What must be the length of a 5mm dia aluminium wine so that it can be twisted through 1 complete revolution without exceeding a shear of 42N/mm2. Take, G=27 GPO.
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