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Term 2 Chapter 3 | 6th Maths - Profit and Loss | 6th Maths : Term 2 Unit 3 : Bill, Profit and Loss

Chapter: 6th Maths : Term 2 Unit 3 : Bill, Profit and Loss

Profit and Loss

the dealer invests some money to buy the goods, spends his time to bring them to his place and he wants to earn a bit more money than his investment. The excess money that the dealer collects from the people is called gain or profit.

Profit and Loss

In our daily life, we use many commodities like food, clothes, vehicles, books etc. Everything is produced by someone or by a team of people and sold directly to the people or through the dealers. When we buy anything, a dealer charges more than what the manufacturer charges. Because, the dealer invests some money to buy the goods, spends his time to bring them to his place and he wants to earn a bit more money than his investment. The excess money that the dealer collects from the people is called gain or profit. If he is in the situation of collecting less money than what he has paid to the manufacturer due to the urgent need of money or some other reason, he loses some money. This losing of money in his investment is called loss. This process of buying and selling goods involves either profit or loss. We shall discuss this in detail.

 

Cost Price (C.P.)

A shopkeeper purchases goods from a manufacturer or a supplier. This is called Purchase Price. He also meets out the overhead expenses like transport charges, wages, etc. So, the Cost Price (C.P.) consists of the capital, the cost of raw materials, the labour charges for production, the electricity charges, the transport charges etc. C.P. = Purchase price + Overhead expenses

For example, ABC Cars, the car manufacturing company buys raw materials for 2,00,000 per car, pays 70,000 to labourers, 15,000 towards electricity bill, 10,000 towards transports. Therefore, the Cost Price (C.P.) of a car produced is 2,00,000 + ₹70,000 + ₹15,000 + ₹10,000 = ₹2,95,000.

Think

The C.P. of a commodity differs from the manufacturer to the dealer or the shopkeeper. Why? Discuss.

Note

The shopkeeper may require to spend some amount to bring the purchased commodities, like transport charges, wages to workers, toll fee etc., which come as part of “overhead expenses “.

 

Marked Price (M.P.)

When a shopkeeper takes the goods from the dealer to his outlet for sales, he has to make profit in his business. So, he marks the price higher than the cost price of the goods. This price is called as Tag price or Marked Price (M.P.).

In the above example, ABC cars likes to make 50,000 as its profit. So, it fixes up the Marked Price (M.P.) of the car as 2,95,000 + 50,000 = 3,45,000.

 

Discount

The reduction of cost on the Marked Price for the purpose of attracting the customers or some other reasons is called Discount.

To increase the sales, ABC cars is ready to reduce 5,000 to its customers, who is buying the car. Here the discount is 5,000.


Note

M.R.P. is Maximum Retail Price, which is fixed by the manufacturer. No commodity can be sold beyond this price.

Think

Which is greater M.P. or C.P

 

Selling Price (S.P.)

The amount that a customer pays to a commodity, after availing the discount (wherever possible) is called as Selling Price (S.P.).

The Marked Price of the car is 3,45,000. The S.P. of the car sold by ABC cars is 3,45,000  − 5,000 = ₹3,40,000. i.e., M.P. Discount = S.P.

From the above discussion we can come to the following conclusions.

•  If C.P. < S.P., there is Profit ⇒ Profit = S.P. − C.P.

• If C.P. > S.P., there is loss ⇒ Loss = C.P. − S.P.

• If C.P. = S.P., there is no profit or loss.

• Discount = M.P. − S.P. (or) S.P. = M.P. − Discount.

• If there is no discount, then M.P. = S.P.

Try these

Arrange in ascending order:

(i) C.P., M.P., Discount

Answer: C.P., M.P,, Discount 

(ii) M.P., S.P., Discount

Answer: M.P., Discount, S.P.,

 

Example 3:

Fill up the appropriate boxes in the following table:


Solution :

(i) C.P. < S.P. ⇒  Profit = S.P. − C.P. = ₹60 − ₹50 = ₹10

(ii) C.P. > S.P. ⇒ Loss = C.P. − S.P. = ₹70 − ₹60 = ₹10

(iii) Profit = S.P. − C.P.

                ⇒ ₹20 = S.P. − ₹100

                 ⇒ S.P. = ₹20 + ₹100 = ₹120

(iv) Loss    = C.P. − S.P.

                   ₹15 = ₹80 − S.P.

                   ⇒ S.P. = ₹80 − ₹15 = ₹65

(v) Profit    = S.P. − C.P.

                    ₹25 = ₹70 − C.P.

                  ⇒ C.P. = ₹70 − ₹25 = ₹45

(vi) Loss     = C.P. − S.P.

                    ₹30 = C.P. − ₹100

                   ⇒ C.P. = ₹30 + ₹100 = ₹130

Think

Which is greater S.P. or M.P.?

 

Example 4A table is bought for  4500 and sold for 4800. Find the profit or loss.


Solution:

C.P. = 4500

S.P. = 4800

Here, C.P. < S.P. ⇒ Profit = S.P. − C.P.

                                       4800 − 4500 = 300

 

Example 5:

 A fruit seller bought a basket of fruits for 500. During the transit some fruits were damaged. So, he was able to sell the remaining fruits for 480. Find the profit or loss in his business.

Solution:

C.P. = 500

S.P. = 480

Here, C.P. > S.P. ⇒ Loss = C.P. − S.P. = 500 − 480 = ₹20

 

Example 6:

 Pari bought a Motor cycle for 55,000 and he gained 5500 on selling the same. What is the selling price of the motor cycle?

Solution:

C.P. = 55,000

Profit = 5,500

Profit = S.P. − C.P.

⇒ 5,500 = S.P. − ₹55,000

⇒ S.P.= 5,500 + 55,000 = 60,500

 

Example 7:

Manimegalai purchased a house for 25,52,500 and spent 2,28,350 for its repair. She sold it for 30,52,000. Find her gain or loss.

Solution:

C.P. = 25,52,500 + 2,28,350 = 27,80,850

S.P. = 30,52,000.

C.P. < S.P. ⇒ Profit = S.P. − C.P.= 30,52,000 − 27,80,850 = ₹2,71,150.

 

Example 8:

A man bought 75 Mangoes for 300 and sold 50 Mangoes for 300.

If he sold all the mangoes at the same price, find his profit or loss.

Solution:

If the man bought 75 Mangoes for 300 then, Cost Price of 1 Mango = 300/75 = 4

If 50 Mangoes were sold for 300 then, Selling Price of 1 Mango is 300/50 = 6

∴ Selling price of 75 Mangoes at the rate of 6 is 75 × 6 = 450

Selling Price > Cost Price

∴ Profit = Selling Price − Cost Price = 450 − 300 = 150

 

Example 9:

A fruit seller bought a dozen apples for 84. 2 apples got rotten. If he has to get a profit of 16, find the S.P. of each apple.

Solution:

Cost price of 12 apples = 84.

Since 2 apples got rotten, the number of remaining apples = 10

Since profit is 16, Selling price of 10 apples = C.P. + Profit = 84 + 16 = 100

∴ Selling price of 1 apple = 100/10 = 10

 

Example 10:

Wheat is being sold at 1550 per bag of 25 kg at a profit of 150. Find the cost price of the wheat bag.

Solution:

Selling price = 1550

Profit = 150

Profit = S.P. − C.P.

 ₹150 = ₹1550 − C.P.

 Cost price = ₹1550 − ₹150 = ₹1400

 

Example 11:

Complete the following table.


Solution:

(i) C.P.  = ₹110

M.P.      = ₹130

Discount = ₹5

S.P.         = M.P. −  Discount

                = ₹130 − ₹5

                = ₹125

Profit = S.P. − C.P.

           = ₹125 − ₹110

           = ₹15

 (ii) C.P.  = ₹110

M.P.       = ₹130

Discount = ₹20

S.P.         = M.P. − Discount

               = ₹130 − ₹20

                = ₹110

C.P. = S.P. ⇒ No profit or No loss.

(iii) M.P.  = ₹130

Discount   = ₹15

S.P.           = M.P. − Discount

                  = ₹130 − ₹15

                  = ₹115

Profit         = ₹30

Profit         = S.P. − C.P.

₹ 30           = ₹115 −  C.P.

C.P.         = ₹115 − ₹30

                = ₹85

(iv) M.P. = ₹130

Loss        = ₹25

S.P.         = M.P. − Discount

               = ₹130 − ₹0

               = ₹130

Loss        = C.P. − S.P.

₹25         = C.P. − ₹130

C.P.        = ₹25 + ₹130

               = ₹155

(v) M.P.   = ₹125

Discount  = ₹0

S.P.         = M.P. − Discount

               = ₹125 −  ₹0

                = ₹125

No profit / No loss

C.P.         = S.P.

C.P.        = ₹125

 (vi) S.P.   = ₹350

Discount   = ₹50

Profit        = ₹100

M.P.         = S.P.+ Discount

                 = ₹350 + ₹50 = ₹400

Profit        = S.P. − C.P.

₹100         = ₹350 − C.P.

C.P.         = ₹350 − ₹100

                = ₹250

 

Example 12:

Barathan offers his customers a discount of 50 on each shirt and still makes a profit of 100 per shirt. What is the actual cost price of the shirt that is marked ₹800?

Solution :

Discount    = ₹50

Profit        = ₹100

M.P.          = ₹800

S.P.           = M.P. − Discount

                 = ₹800 − ₹50

                 = ₹750

Profit       = S.P. − C.P.

₹100        = ₹750 − C.P.

C.P.         = ₹750 − ₹100

                = ₹650

 

Example 13:

Raghu buys a chair for 3000. He wants to sell it at a profit of 500 after making a discount of 300. What is the M.P. of the chair?

Solution :


C.P. = ₹3000; Profit = ₹500; Discount = ₹300

 S.P. = M.P. − Discount = M.P. − ₹300

Profit = S.P. − C.P.

₹500 = M.P. − ₹300 − ₹3000

M.P. = ₹500 + ₹300 + ₹3000 = ₹3800

 

Example 14:

Mani buys a gift article for 1500. He wants to sell it at a profit of 150 on sales and he marks @ ₹1800. What is the discount that he will give to his customers ?

Solution :

C.P. =  ₹1500; Profit = ₹150; M.P. = ₹1800

S.P. = M.P. − Discount = ₹1800 − Discount

Profit = S.P. − C.P. ⇒ ₹150 = ₹1800 − Discount − ₹1500

Discount = ₹1800 − ₹1500 − ₹150 = ₹150

 

ICT CORNER

BILL, PROFIT and LOSS

Expected Outcome


Step 1 Open the Browser and type the URL Link given below (or) Scan the QR Code. GeoGebra work sheet named “Profit and Loss” will open. The work sheet contains two activities. Click on “New Problem to change the problem. Read the given problem carefully.

Step 2 Work out yourself and check whether the answer is correct.

Tags : Term 2 Chapter 3 | 6th Maths , 6th Maths : Term 2 Unit 3 : Bill, Profit and Loss
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6th Maths : Term 2 Unit 3 : Bill, Profit and Loss : Profit and Loss | Term 2 Chapter 3 | 6th Maths


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