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Chapter: 6th Maths : Term 2 Unit 3 : Bill, Profit and Loss

Exercise 3.1

6th Maths : Term 2 Unit 3 : Bill, Profit and Loss : Text Book Back Exercises Questions with Answers, Solution

Exercise 3.1

 

1. A school purchases some furniture and gets the following bill.


Questions:

(i) What is the name of the store?

Mullai Furniture Mart

(ii) What is the serial number of the bill?

Serial No. 728

(iii) What is the cost of a black board?

The cost of a black board is ₹ 3000

(iv) How many sets of benches and desks does the school buy?

The school buys 50 sets of benches and desks.

(v) Verify whether the total bill amount is correct.

The total bill amount is correct.

 

2. Prepare a bill for the following books of biographies purchased from Maruthu Book Store, Chidambaram on 12.04.2018 bearing the bill number 507.

10 copies of Subramanya Bharathiar @ ₹55 each, 15 copies of Thiruvalluvar @ ₹75 each, 12 copies of Veeramamunivar @ ₹60 each and 12 copies of  Thiru.Vi. Ka @ ₹70 each.

Answer:


 

3. Fill up the appropriate boxes in the following table.


i) C.P < S.P

Profit = S.P − C.P

= ₹120 − ₹ 100

= ₹ 20

ii) C.P < S.P

Profit = S.P − C.P

= ₹ 120 − ₹ 110

= ₹ 10

iii) Profit = S.P < C.P

₹ 20 = S.P − ₹ 120

S.P = ₹ 20 − ₹ 120

= ₹ 140

iv) C.P > S.P

Loss = C.P − S.P

= ₹ 100 − ₹ 90

= ₹ 10

v) Profit = S.P − C.P

₹ 25 = S.P − ₹ 120

S.P = ₹ 25 + ₹ 120

= ₹ 145


 

4. Fill up the appropriate boxes in the following table.


i) C.P  = ₹ 110

M.P = ₹ 130

Discount = Nil

S.P = M.P − Discount

= ₹ 130 – 0

= ₹ 130

C.P < S.P

Profit = S.P − C.P

= ₹ 130 − ₹ 110

= ₹ 20

ii) C.P = ₹ 110

M.P = ₹ 130

Discount = ₹ 10

S.P M.P − Discount

= ₹ 130 − ₹ 10

= ₹ 120

C.P < S.P

Profit = S.P − C.P

= ₹ 120 − ₹ 110

= ₹ 10

iii) C.P = ₹ 110

M.P = ₹ 130

Discount = ₹  30

S.P = M.P − Discount

= ₹ 130 − ₹ 30

= ₹ 100

C.P > S.P

Loss = C.P − S.P

= ₹ 110 − ₹ 100

= ₹ 10

iv) C.P = ₹ 100

M.P = ₹ 120

Loss = ₹ 10

S.P = C.P − Loss

= ₹ 100 − ₹ 10

= ₹ 90

S.P = M.P − Discount

₹ 90 = ₹ 120 − Discount

Discount = ₹ 120 − ₹ 90

= ₹ 30

v) M.P = ₹ 120

Discount = ₹ 10

Profit = ₹ 20

S.P = M.P − Discount

= ₹  120 − ₹ 10

= ₹  110

C.P = S.P − Profit

= ₹ 110 − ₹ 20

= ₹ 90


 

5. Rani bought a set of bangles for ₹310. Her neighbour liked it most. So, Rani sold it to her for ₹325. Find the profit or loss to Rani.

C.P = ₹ 310

S.P = ₹ 325

C.P < S.P

Profit = S.P − C.P

= ₹ 325 − ₹ 310 = ₹ 15

Profit = ₹ 15

 

6. Sugan bought a Jeans pant for ₹750. It did not fit him. He sold it to his friend for ₹710. Find the profit or loss to sugan.

C.P = ₹ 750

S.P = ₹ 710

C.P > S.P

Loss = C.P − S.P

= ₹ 750 − ₹ 710 = ₹ 40

Loss = ₹ 40

 

7. Somu bought a second hand bike for ₹28,000 and spent ₹2,000 on its repair. He sold it for ₹30,000. Find his profit or loss.

C.P = ₹ 28,000

Repairing Charge = ₹ 2,000

Total C.P = ₹ 30,000

S.P = ₹ 30,000

C.P = S.P

No profit / Loss 

 

8. Muthu has a car worth ₹8,50,000 and he wants to sell it at a profit of ₹25,000. What should be the selling price of the car?

C.P = ₹8,50,000

Profit = ₹ 25,000

S.P = C.P + Profit

= ₹ 8,50,000 − ₹ 25,000

= ₹ 8,75,000

 

9. Valarmathi sold her pearl set for ₹30,000 at profit of ₹5000. Find the cost price of the pearl set.

S.P = ₹ 30,000

Profit = ₹ 5,000

C.P = S.P − Profit

= ₹ 30,000 − ₹ 5,000

= ₹ 25,000

 

10. If Guna marks his product to be sold for ₹325 and gives a discount of ₹30, then find the S.P.

M.P = ₹ 325

Discount = ₹ 30

S.P = M.P − Discount

= ₹ 325 − ₹ 30

= ₹ 295

 

11. A man buys a chair for ₹1500. He wants to sell it at a profit of ₹250 after making a discount of ₹100. What is the M.P. of the chair?

C.P = ₹ 1500

Discount = ₹ 100

Profit = ₹ 250

S.P = C.P + Profit

= ₹ 1500 + ₹ 250

= ₹ 1750

S.P = M.P −  Discount

₹ 1750 = M.P − ₹ 100

M.P = ₹ 1750 + ₹ 100

= ₹ 1850

 

12. Amutha marked her home product of pickle as ₹300 per pack. But she sold it for only ₹275 per pack. What was the discount offered by her per pack?

M.P = ₹ 300

S.P = ₹ 275

S.P = M.P − Discount 

₹ 275 = ₹ 300 − Discount

Discount = ₹ 300 − ₹ 275

= ₹ 25

 

13. Valavan bought 24 eggs for ₹96. Four of them were broken and also he had a loss of ₹36 on selling them. What is the selling price of one egg?

Cost price of 24 eggs = ₹ 96

Loss = ₹ 36

Selling price  = Cost price − Loss

= ₹ 96 − ₹ 36

= ₹ 60

Number of eggs broken = 4

Remaining eggs = 24 − 4 = 20

Selling price of 20 eggs = ₹ 60

Selling price of one egg = ₹ 60 ÷ 20 = ₹ 3

Selling price of one egg = ₹ 3

 

14. Mangai bought a cell phone for ₹12585.  It fell down. She spent ₹500 on its repair. She sold it for ₹7500. Find her profit or loss.

Cost price = ₹ 12,585

Repairing charge = ₹ 500

Total cost price = ₹ 13,085

Selling price = ₹ 7,500

C.P > S.P

Loss = C.P − S.P

= ₹ 13,085 − 7,500 = ₹ 5,585

Loss = ₹ 5,585

 

Objective Type Questions

 

15. Discount is subtracted from ——— to get S.P.

 (a) M.P.

 (b) C.P.

 (c) Loss

 (d) Profit

Answer: a) M.P.

 

16. ‘Overhead expenses’ is always included in ———.

(a) S.P.

(b) C.P.

(c) Profit

(d) Loss

Answer: b) C.P.

 

17. There is no profit or loss when

 (a) C.P. = S.P.

(b) C.P > S.P.

 (c) C.P < S.P.

(d) M.P. = Discount

Answer: a) C.P. = S.P.

 

18. Discount = M.P.  .............

(a) Profit

(b) S.P.

(c) Loss

(d) C.P.

Answer: b) S.P.

 

ANSWERS:

Exercise 3.1

1. i) Mullai Furniture mart ii) Serial No: 728 iii) ₹3000 iv) 50 sets v) correct

2.  

3. i) Profit = ₹20 ii) Profit = ₹10 iii) S.P. = ₹140 iv) Loss = ₹10 v) S.P. = ₹145

4. i) S.P. = ₹130 Profit = ₹20

ii) S.P. = ₹120 Profit = ₹10

iii) S.P. = ₹100 Loss = ₹10

iv) S.P. = ₹90 Discount = ₹30

v) S.P. = ₹110 C.P. = ₹90

5. Profit = ₹15

6. Loss = ₹40

7. No Profit / Loss

8. S.P. = ₹8,75,000

9. C.P. = ₹25,000

10. Discount = ₹295

11. M.P. = ₹1850

12. Discount = ₹25

13. S.P = ₹3

14. Loss = ₹5585

Objective Type Questions

15. (a) M.P.

16. (b) C.P

17. (a) C.P = S.P

18. (b) S.P

 

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6th Maths : Term 2 Unit 3 : Bill, Profit and Loss : Exercise 3.1 | Questions with Answers, Solution | Bill, Profit and Loss | Term 2 Chapter 3 | 6th Maths


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