Boundary Layer
Introduction
Hydraulic gradient line.
It
is defined as the line which gives the sum of pressure head ( P/?g) and datum
head (z) of a flowing fluid in a pipe with respect to some reference line or is
the line which is obtained by joining the top of all vertical ordinates,
showing the pressure head ( P/?g) of a pipe from the center of the pipe. It is
briefly written as H.G.L
Major
energy loss and minor energy loss in pipe
The loss of head or
energy due to friction in pipe is known as major loss while the loss of energy
due to change of velocity of the flowing fluid in magnitude or direction is
called minor loss of energy.
Total Energy line
It is defined as the
line, which gives sum of pressure head, datum head and kinetic head of a
flowing fluid in a pipe with respect to some reference line.
Equivalent pipeline
An Equivalent pipe is
defined as the pipe of uniform diameter having loss of head and discharge of a
compound pipe consisting of several pipes of different lengths and diameters.
Water Hammer in pipes.
In
a long pipe, when the flowing water is suddenly brought to rest by closing the
valve or by any similar cause, there will be a sudden rise in pressure due to
the momentum of water being destroyed. A pressure wave is transmitted along the
pipe. A sudden rise in pressure has the effect of hammering action on the walls
of the pipe. This phenomenon of rise in pressure is known as water hammer or
hammer blow.
The
boundary layer is called laminar, if the Renolds number of the flow is defined
as Re = U x X / v is less than 3X105
If
the Renolds number is more than 5X105, the boundary layer is called
turbulent boundary.
Where,
U = Free stream velocity of flow X = Distance from leading edge v = Kinematic
viscosity of fluid
Chezy's formula.
Chezy's formula is generally used for
the flow through open channel.
V =C.Rt(mi)
Where , C = chezy's constant, m =
hydraulic mean depth and i = hf/ L.
Problem
1
A
crude of oil of kinematic viscosity of 0.4 stoke is flowing through a pipe of
diameter 300mm at the rate of 300 litres/sec. find the head lost due to
friction for a length of 50m of the pipe.
Problem
2
Find
the type of flow of an oil of relative density 0.9 and dynamic viscosity 20 poise,
flowing through a pipe of diameter 20 cm and giving a discharge of 10 lps.
Solution :
s = relative density =
Specific gravity = 0.9 m =
Dynamic viscosity = 20 poise = 2 Ns/m2.
Dia of pipe D = 0.2 m; Discharge Q = 10
lps = (10 / 1000) m3/s; Q =
AV. So V = Q / A = [10 / (1000 X ( p4 ( 0.2)2) )] = 0.3183 m/s.
Kinematic viscosity = v = m / ? = [ 2 / (0.9X1000)] = 2.222X10-3 m2 / s.
Reynolds number Re = VD / v
Re = [0.3183 X 0.2 / 2.222X10-3] = 28.647; Since Re ( 28.647) < 2000,
It is Laminar flow.
Formula
for finding the loss of head due to entrance of pipe hi
hi = 0.5 (
V2 / 2g)
Formula
to find the Efficiency of power transmission through pipes
n = ( H - hf) / H
where, H = total head at inlet of pipe. hf = head lost due to friction
Problem
3
Hydro
dynamically smooth pipe carries water at the rate of 300 lit/s at 20oC
(r = 1000 kg/m3, n = 10-6 m2/s) with
a head loss of 3m in 100m length of pipe.
Determine the pipe diameter. Use f =
0.0032 + (0.221)/ (Re)0.237 equation for f where hf = ( fXLXV2)/
2gd and Re = (rVD/m)
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