ITERATIVE SOLUTION USING NEWTON-RAPHSON METHOD – ALGORITHM
Step 1: Assume a suitable solution for all buses except the slack bus. Let Vp = a+j0 for P
= 2,3,……n V1 = a+j0
Step 2 : Set the convergence criterion = ε0
Step 3 : Set iteration count K= 0
Step 4 : Set bus count P = 2
Step 5 : Calculate Pp and Qp using n
Step 6 : Evaluate ΔPPK = Pspec - PPK
Step 7 : Check if the bus is the question is a PV bus. If yes compare QPK with the limits. If it exceeds the limit fix the Q value to the corresponding limit and treat the bus as PQ for that iteration and go to next step (or) if the lower limit is not violated evaluate │ΔVP│2 = │ Vspec│2 - │VPK│2 and go to step 9
Step 8: Evaluate ΔQPK = Qspec - QPK
Step 9 : Advance bus count P = P+1 and check if all buses taken in to account if not go to step 5
Step 10 : Determine the largest value of │ΔVP│2
Step 11: If ΔVP < ε go to step 16
Step 12: Evaluate the element of Jacobin matrices J1, J2, J3, J4, J5 and J6
Step 13: Calculate ΔePK and ΔfPK
Step 14: Calculate ePK+1 = ePK + ΔePK and fPK+1 = fPK + ΔfPK
Step 15 : Advance count (iteration) K=K+1 and go to step 4
Step 16: Evaluate bus and line power and print the result
Advantages: Faster, more reliable and results are accurate, require less number of iterations;
Disadvantages: Program is more complex, memory is more complex.
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